如何在python中将“ASCII”转换为“hex”

Question

How to convert "ASCII" to "HEX" in python

I have one file need to read . but use below code it only can show ASCII

with open('Hello.DAT','rb') as f:
    data= f.read()  
    print(data)

It can print data in this format:

01201602180000020000000007000000000054000000000000\\x0

How do I to convert this data to HEX values, like this:

30 31 32 30 31 36 30 32 31 38 30 30 30 30 30 32 30 30 30 30 30 30 30 30 30 37 30 30 30 30 30 30 30 30 30 30 35 34 30 30 30 30 30 30 30 30 30 30 30 30 5c 78 30

Answer 1

Assuming python3:

with open('Hello.DAT','rb') as f:
    data = f.read()  
    print(" ".join("{:02x}".format(c) for c in data))

(in python2 change format(c) to format(ord(c)) )

Answer 2

You can just encode to hex:

In [6]: with open("test.txt") as f:
         print(" ".join([ch.encode("hex")  for line in f for ch in line]))
...:     
30 31 32 30 31 36 30 32 31 38 30 30 30 30 30 32 30 30 30 30 30 30 30 30 30 37 30 30 30 30 30 30 30 30 30 30 35 34 30 30 30 30 30 30 30 30 30 30 30 30 5c 78 30 0a

Or for python3 just call hex:

In [18]: with open("test.txt", "rb") as f:            
            print(" ".join([hex(ch)[2:]  for line in f for ch in line]))  
 ....:     
30 31 32 30 31 36 30 32 31 38 30 30 30 30 30 32 30 30 30 30 30 30 30 30 30 37 30 30 30 30 30 30 30 30 30 30 35 34 30 30 30 30 30 30 30 30 30 30 30 30 5c 78 30 a