[英]Recursive program reaches return statement, but jumps back to call in method
When I run this program through eclipse's debugger, in the method randomRecursion
, once i is less than 0
, it skips to the return, but then jumps back up to the randomRecursion
call. 当我通过eclipse的调试器运行该程序时,在
randomRecursion
方法中,一旦i小于0
,它就会跳到返回值,然后又跳回到randomRecursion
调用。 Why is this? 为什么是这样?
public class RecursiveExample {
public static double randomRecursion(double a, double b, int i) {
while (i > 0) {
b = ((1 / a) - a) * b;
i = i - 1;
randomRecursion(a, b, i);
}
return b;
}
public static void main(String[] args) {
for (int i = 0; i < 5; i++)
System.out.println(randomRecursion(.5, .5, i));
}
}
Calling the recursive method doesn't terminate your method - you missed the return
there. 调用递归方法不会终止您的方法-您错过了那里的
return
。 Once you've done that, as @pjs mentioned in the comments, you really have no need for a while
loop - you just need a simple conditional statement: 完成此操作后,正如注释中提到的@pjs一样,您实际上不需要
while
循环-您只需要一个简单的条件语句:
public static double randomRecursion(double a, double b, int i) {
if (i > 0) {
b = ((1 / a) - a) * b;
i = i - 1;
// return was missing here
return RandomRecursion(a, b, i);
}
return b;
}
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