如何在Python的同一行上打印来自不同函数的两个语句

Question

I'm trying to print two output statements on the same line in Python 2.7 (or 3.4). The print statements don't come one after the other Like print a/ print b. My program takes 329 (say) and returns that value in words - three hundred twenty nine. So it will determine the 300 part and print it then the 29 part and print that.

if (main == hundreds[index]):
    print hundreds_words[index]
for location in range (0, 10):
    if (difference == twenties[location]):
        print twenties_words[location]

I want to print the twenty nine on the same line as the three hundred. I suppose I could try and rig up a solution but I would like to know if Python has a procedure to do that.

Answer 1

Yes, it does. You just need to tell print not to add a new-line after the first one. In python2, you do this by adding a trailing comma: print mystring, . In python3, print is a function that has the end keyword argument: print(mystring, end="")

Answer 2

The easy way is to rewrite your number-to-words function and have it return a string instead of printing it.

The more involved way is to redirect stdout to capture the print output as a string.

Edit: looks like I made it more complicated than necessary; you could instead try

output_words = []
if (main == hundreds[index]):
    output_words.append(hundreds_words[index])
for location in range (0, 10):
    if (difference == twenties[location]):
        output_words.append(twenties_words[location])
return " ".join(output_words)

Answer 3

In python 2 you can end a print statement with a , to indicate not to terminate in a newline, eg:

print hundreds_words[index], 

In python 3 (or py2 with from __future__ import print_function ) you explicitly need to define the end , eg:

print(hundreds_words[index], end=' ')

But ideally you would just collect all the result up in a list and join() them at the end...

result = []
if (main == hundreds[index]):
    result.append(hundreds_words[index])
for location in range (0, 10):
    if (difference == twenties[location]):
        result.append(twenties_words[location])

print(' '.join(result))

Answer 4

Always design functions to return values, and not to print them (it's much more Pythonic!). Therefore, you should modify your code this way:

# FOR PYTHON 2.x

if (main == hundreds[index]):
    print hundreds_words[index], # Note the comma
for location in range (0, 10):
    if (difference == twenties[location]):
        print twenties_words[location]

# FOR PYTHON 3.x

if (main == hundreds[index]):
    print(hundreds_words[index], end=" ") # end=" " will override the default '\n' and leave a space after the string
for location in range (0, 10):
    if (difference == twenties[location]):
        print(twenties_words[location])

There's also a third option, more scalable: to wrap all datas in a list, and then print everything.

printable = []

if (main == hundreds[index]):
    printable += hundreds_words[index]
for location in range (0, 10):
    if (difference == twenties[location]):
        printable += twenties_words[location]

print(" ".join(printable))