为什么它永远不会进入for循环？

Question

This is my first time asking a question on stack overflow. My switch statement which switched on an enumerated type inputted by the user is only working for case: QUIT . Here is my code:

int get_function(menu_t get_input)
{
    int i;
    double rad, result;


    switch ( get_input )
    {
    case Sin:

        i = 0;

        for (i = 0; i > loop_limit; i += step_size)
        {
            rad = PI * (i /180);

            result = sin(rad);

            printf("\tsin(%d) = %.4lf\n", i, result);
            printf("\n");
        }


    break;

    case Cos:

        for(i = 0; i > loop_limit; i += step_size)
        {       
            rad = PI * (i /180);

            result = cos(rad);

            printf("\tcos(%d) = %.4lf\n", i, result);
            printf("\n");
        }


    break;

    case Tan:


        for(i = 0; i > loop_limit; i += step_size)
        {
            if(i <= 75)
            {   
                rad = PI * (i /180);

                result = tan(rad);

                printf("\ttan(%d) = %.4lf\n", i, result);
                printf("\n");
            }
            else
            {
                printf("\ttan(%d) is UNDEFINED", i);
            }
        }


    break;

    case QUIT:

        printf("You chose QUIT. Thank you, come again!\n");
    break;


        }
    return(0);
}   

As you can see I'm using for loops inside the cases that aren't executing... is this the problem? Thanks to anyone who can help me with this...

Answer 1

There is a typo in your for loops. With this writing :

for(i = 0; i > loop_limit; i += step_size)

You will set i = 0 and ask the work being done as long as i > loop_limit ... so, never.

The correct writing is :

for(i = 0; i <= loop_limit; i += step_size)