转义双引号Oracle使用Java准备了Statement

Question

I checked similar asked questions but did not have an acceptable solution. A table with a list of quoted values in a column:

ROW  COLOR_ARRAY
===  ============
1    "RED", "BLUE", "GREEN", "LIGHT-BLUE"
2    "RED", "GREEN", "LIGHT-BLUE"

I want to pull all rows who contains exact value "BLUE" so, row 1 should only be returned. my prepared statement:

        // must look for color wrapped in double quotes "BLUE"
        String sql = "Select * from myTable where COLOR_ARRAY LIKE '%\"?\"%'";
        selectColor = connection.prepareStatement(sql);
        String myColor = "BLUE";
        selectTags.setString(1, myColor);
        rs = selectTags.executeQuery();

I'm getting a Invalid column index error. I suspect the ? mark in my prepared statement is getting lost in trying to esacape the double quotes in my LIKE clause.

I've tried escaping the double quotes with \\\\" and " but no luck.

Answer 1

In JDBC, you cannot place a placeholder ? within an existing SQL string; the value must be standalone. JDBC will treat a ? within a SQL string as a literal ? character; it's just part of the string. Escaping the double-quotes characters within the Java string is correct, however.

Concatenate the ? placeholder value with the % SQL wildcard strings in the query string.

String sql = "Select * from myTable where COLOR_ARRAY LIKE '%\"' || ? || '\"%'";