表格单元格内的UIButton不会在Swift中锁定到视图控制器

Question

I have a problem I can not solve it anywhere. I have a view controller with a table view inside it. This table view is shown some data and has a button to move on to another view controller through certain data of the line to the button. But unfortunately I can not even move on to the other view controller. Already tried using only the Storyboard, and programmatically via protocols / delegate. Can someone help me? Storyboard

Follow some code: func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int { return NumberOfRows }

func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
    var Cont = 0
    for var i = indexPath.row ; i>0; i-- {
        Cont += QuantidadeCombustivel[i]
    }
    let cell = tableView.dequeueReusableCellWithIdentifier("PostoTableViewCell", forIndexPath: indexPath) as! PostoTableViewCell

    if (self.NomesArray.count != 0) && (self.imagensArray.count != 0) {
        cell.NomePosto.text = self.NomesArray[indexPath.row]
        cell.BandeiraPosto.imageFromUrl(self.imagensArray[indexPath.row])
        cell.distanciaLabel.text = "Distância: \(self.DistanciaArray[indexPath.row])"
        var result = ""
        for i in Cont...Cont+self.QuantidadeCombustivel[indexPath.row+1]-1 {
            result += ("\(self.NomeCombustivel[i]) : \(self.ValorCombustivel[i])\n")
        }
        cell.ListaCombustivel?.text = result;

    }


    return cell
}

func tableView(tableView: UITableView, didSelectRowAtIndexPath indexPath: NSIndexPath) {
    openMapForPlace(indexPath.row)
}

class PostoTableViewCell: UITableViewCell {

@IBOutlet weak var BandeiraPosto: UIImageView!

@IBOutlet weak var NomePosto: UILabel!

@IBOutlet weak var ListaCombustivel: UITextView!

@IBOutlet weak var distanciaLabel: UILabel!

@IBOutlet weak var SgInfoPosto: UIButton!

Answer 1

You have to do this

func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
    let cell = tableView.dequeueReusableCellWithIdentifier("Cell") as! TableViewCell

    cell.button.tag = indexPath.row

    return cell

}

and

@IBAction func buttonPressed(sender: AnyObject) {
    print(sender.tag)
    self.performSegueWithIdentifier("yourSegueIdentifier", sender: tableView)
}

Answer 2

Consider 2 ViewCOntrollers , the one with button let's say it as FirstVC and the destination is called as SecondVC.Check is your FirstVC embedded in Navigation Controller?.If No then firstly embed it into navigation controller.Click on FirstVC , then click on Editor tab , inside it click on embed , then embed in Navigation Controler , then Give a segue from FirstVC to SecondVC in storyboard. After that write the below code in your button action method.

[self performSegueWithIdentifier:@"SegueIdentifier" sender:nil];

In the sender , you can pass your array as well.

Then write a method

- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
{
      SecondVC *destination = [segue destinationViewController];
}

Or else you can use Below code as well In your button action method , write the below code

UIStoryboard *storyboard = [UIStoryboard storyboardWithName:@"Storyboard" bundle:nil];

 SecondVC* secondVC = [storyboard instantiateViewControllerWithIdentifier:@"StoryboardIdentifier"];
[self.navigationController pushViewCpntroller:secondVC animated:YES];