用空格替换除词内破折号之外的标点符号

Question

There already is an approaching answer in R gsub("[^[:alnum:]['-]", " ", my_string) , but it does not work in Python:

my_string = 'compactified on a calabi-yau threefold @ ,.'
re.sub("[^[:alnum:]['-]", " ", my_string)

gives 'compactified on a calab yau threefold @ ,.'

So not only does it remove the intra-word dash, it also removes the last letter of the word preceding the dash. And it does not remove punctuation

Expected result (string without any punctuation but intra-word dash): 'compactified on a calabi-yau threefold'

Answer 1

R uses TRE (POSIX) or PCRE regex engine depending on the perl option (or function used). Python uses a modified, much poorer Perl-like version as re library. Python does not support POSIX character classes , as [:alnum:] that matches alpha (letters) and num (digits).

In Python, [:alnum:] can be replaced with [^\\W_] (or ASCII only [a-zA-Z0-9] ) and the negated [^[:alnum:]] - with [\\W_] ( [^a-zA-Z0-9] ASCII only version).

The [^[:alnum:]['-] matches any 1 symbol other than alphanumeric (letter or digit), [ , ' , or - . That means the R question you refer to does not provide a correct answer .

You can use the following solution :

import re
p = re.compile(r"(\b[-']\b)|[\W_]")
test_str = "No -  d'Ante compactified on a calabi-yau threefold @ ,."
result = p.sub(lambda m: (m.group(1) if m.group(1) else " "), test_str)
print(result)

The (\\b[-']\\b)|[\\W_] regex matches and captures intraword - and ' and we restore them in the re.sub by checking if the capture group matched and re-inserting it with m.group(1) , and the rest (all non-word characters and underscores) are just replaced with a space.

If you want to remove sequences of non-word characters with one space, use

p = re.compile(r"(\b[-']\b)|[\W_]+")