[英]Segmentation fault using strcmp (Ubuntu)
I have the following code segment: 我有以下代码段:
token = strtok(line, separator);
i = 0;
args[i++] = token; /* build command array */
while( token != NULL ) /* walk through other tokens */
{
/* printf( " %s\n", token ); */
token = strtok(NULL, separator);
if (strcmp(token, "|") != 0) {
printf("entered");
}
else {
args[i++] = token;
} /* and build command array */
The code compiles fine, but upon execution passing any argument, I receive the error "Segmentation fault (Core dumped)". 代码可以正常编译,但是在执行时传递任何参数,都会收到错误“分段错误(核心已转储)”。 Removing the if statement comparing the 2 strings solves the issue, so it is a problem with that comparison. 删除比较两个字符串的if语句即可解决此问题,因此该比较存在问题。
When strtok
does not find next token it returns NULL
, thus the segfault when trying to strcmp(NULL, "|")
当strtok
找不到下一个令牌时,它返回NULL
,因此在尝试strcmp(NULL, "|")
Test if token
is null before strcmp
. 测试strcmp
之前token
是否为null。
the posted code: 发布的代码:
token = strtok(line, separator);
i=0;
args[i++]=token; /* build command array */
while( token != NULL ) /* walk through other tokens */
{
/* printf( " %s\n", token ); */
token = strtok(NULL, separator);
if (strcmp(token, "|") != 0) {
printf("entered");
}
else {
args[i++] = token;
} /* and build command array */
contains a logic error. 包含逻辑错误。 the returned value from strtok()
is being used before being checked. 在检查之前,将使用从strtok()
返回的值。
suggest something similar to: 建议类似以下内容:
i=0;
token = strtok(line, separator);
while( token != NULL ) /* walk through other tokens */
{
/* printf( " %s\n", token ); */
if (strcmp(token, "|") != 0)
{
printf("entered");
}
else
{
args[i++] = token;
} /* and build command array */
...
token = strtok(NULL, separator);
} // end while
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.