[英]Convert curl command to httparty
I am trying to add merge field in Mailchimp V3 list with HTTParty but not able to convert curl to HTTParty format. 我正在尝试使用HTTParty在Mailchimp V3列表中添加合并字段,但无法将curl转换为HTTParty格式。
Curl Request format which is working fine : 卷曲请求格式,效果很好:
curl --request POST \
--url 'https://usxx.api.mailchimp.com/3.0/lists/17efad7sd4/merge-fields' \
--user '12:d1c1d99dr5000c63f0f73f64b88e852e-xx' \
--header 'content-type: application/json' \
--data '{"name":"FAVORITEJOKE", "type":"text"}' \
--include
Httparty format with error API key missing 缺少错误API密钥的Httparty格式
response = HTTParty.post("https://us12.api.mailchimp.com/3.0/lists/17efad7sde/merge-fields",
:body => {
:user => '12:d1c1d99dr5000c63f0f73f64b88e852e-xx',
:data => '{"name":"FAVORITEJOKE", "type":"text"}',
:include => ''
}.to_json,
:headers => { 'Content-Type' => 'application/json' } )
I also try it without include option but not working 我也尝试了没有包含选项但无法正常工作
There are several errors in your code. 您的代码中有几个错误。
user
is the basic auth user, but you are passing it in the payload of the request user
是基本的auth用户,但是您正在将其传递到请求的有效负载中 This should be the correct version. 这应该是正确的版本。 Please take a moment to read the
HTTParty
and curl
documentation and understand the differences. 请花一点时间阅读
HTTParty
和curl
文档,并了解它们之间的区别。
HTTParty.post(
"https://us12.api.mailchimp.com/3.0/lists/17efad7sde/merge-fields",
basic_auth: { username: "12", password: "d1c1d99dr5000c63f0f73f64b88e852e-xx" },
headers: { 'Content-Type' => 'application/json' },
body: {
name: "FAVORITEJOKE",
type: "text",
}.to_json
)
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