[英]How to parse JSON string with array in php
I am sending a JSON string in php post request. 我在php post请求中发送JSON字符串。 JSON string look like this:
JSON字符串如下所示:
{"mobile":"0000000000","otp":"970996", "items":[{"pid":"12", "vid":"20"},{"pid":"13", "vid":"2"}]}
At server side i want to get mobile, otp and pid and vid for all items. 在服务器端,我想为所有项目获取移动,OTP,PID和vid。
I am getting mobile number from this: 我从这里得到手机号码:
$data = json_decode(file_get_contents('php://input'), true);
//print_r($data);
echo $data["mobile"];
But when i am trying to get pid and vid like this: 但是当我试图像这样获取pid和vid时:
foreach($data["items"] as $mydata){
echo $mydata->pid;
}
i am getting error: Trying to get property of non-object. 我收到错误:尝试获取非对象的属性。
How to solve this? 如何解决呢?
Edit: 编辑:
If there is any better way to parse JSON in php, please suggest that also. 如果有更好的方法来解析php中的JSON,请同时提出。
Just access pid
with: 只需使用以下命令访问
pid
:
$mydata['pid']
You pass true
as a second argument for json_decode
您将
true
作为json_decode
的第二个参数json_decode
When TRUE, returned objects will be converted into associative arrays.
如果为TRUE,则返回的对象将转换为关联数组。
So you have to treat is as an array, not an object. 因此,您必须将其视为数组,而不是对象。
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