Python Selenium（如果字符串包含完全匹配）

Question

I am trying to check a URL using python selenium to see what page the site is on. I have the following urls...

http://www.example.com
http://www.example.com/page1
http://www.example.com/contact

I am using this python...

if "http://www.example.com" in url:
    print("The URL is homepage")
else:
    print("The URL is not homepage")

This isn't working because all of the URL contain the string, how can I change it so that it only works for an exact match?

Answer 1

Use the equality operator == as follows:

if url == "http://www.example.com":
    print("The URL is homepage")
else:
    print("The URL is not homepage")

It is convention to put the variable name on the LHS of the equality operator and the string you are testing it against on the RHS.

Answer 2

If you want to go a step further, you can use regular expressions

import re

a = re.compile('.*example\.com$')
# .* ignores whatever comes before example.com
# \. escapes the dot
# $  indicates that this must be the end of the string

if a.match(url):  # <-- That's the URL you want to check
    print("The URL is homepage")
else:
    print("The URL is not homepage")