遍历子目录并对某些文件执行awk脚本

Question

I have a directory named ../words that contains a number of subdirectories(words/blabla,words/blabla), in turn each subdirectory contains two types of files (.*1.txt) and (.*2.txt) . What I need, it is to execute an AWK script against each one of these files.

Could it be something like?

for d in words/*
do
    for f in .*[0-9].txt
    do
    awk -f script.awk ${f}
    done
done

Answer 1

If you want to keep your for statement structure and apply the awk script to each specified file, you can do the following:

for file in $(find words -type f -name ".*[12].txt"); do
    awk -f script.awk "$file"
done

The find command is useful for recursively looking through a directory for any pattern of files.

---

Edit: If your file names contain things like spaces, the above script may not process them properly, so you can do the following instead:

find words -type f -name ".*[12].txt" -print0 | while read -d $'\0' file
do 
    awk -f script.awk "$file"
done

or using xargs:

find words -type f -name ".*[12].txt" -print0 | xargs -0 awk -f script.awk

This allows you to delimit your file names with null \\0 characters, so variations in name spacing or other special characters will not be a problem. (You can find more information here: Filenames with spaces breaking for loop, and find command , or here: Handling filenames with spaces , or here: loop through filenames returned by find ).

Answer 2

鉴于您到目前为止告诉我们的内容，这应该是您所需要的：

awk -f script.awk ../words/blabla/.*[12].txt

Answer 3

如果您需要跳过中间目录级别，仅查看子目录下的内容，则可以使用最大/最小深度

$ find words -maxdepth 2 -mindepth 2 -type f -name '*[0-9].txt' | xargs awk -f ...