如何在python3中跳转到随机函数

Question

i am making a python script that talks back to just for fun and i want it to pick a random subject to talk about each time here is a snippet of my code

def randsub():
     rand = random.randrange(1,3)
     rand.toString()
     randsub = "sub" + rand
     randsub()

but it keeps giveing me this error TypeError: Can't convert 'int' object to str implicitly

Answer 1

Put the functions in a list, then use the random.choice() function to pick one at random for you. Functions are just objects, just like any other value in Python:

import random

def sub_hello():
    print('Well, hello there!')

def sub_nice_weather():
    print("Nice weather, isn't it?")

def sub_sports():
    print('What about them Broncos, eh?')

chat_functions = [sub_hello, sub_nice_weather, sub_sports]
randsub = random.choice(chat_functions)
randsub()

You got your specific error because you tried to concatenate an integer with a string ( "sub" is a string, rand an integer); you'd normally convert the integer to a string first, or use a string template that supports converting other objects to strings for you (like str.format() or str % (values,) ). But the string doesn't turn into a function, even if the string value was the same as a function name you happen to have defined.