简体   繁体   English

PHP如果给定日期是日期范围

[英]PHP If given date is date range

I'm trying to determine if the given date $my_date (dynamic) is this week , last week , this month , last month and last 3 months 我正在尝试确定给定的日期$my_date (动态)是否是this weeklast weekthis monthlast monthlast 3 months

$my_date = "29/02/2016";
$scheduled_job = strtotime($my_date);
$this_week = strtotime("first day this week");
$last_week = strtotime("last week monday");
$this_month = strtotime("first day this month");
$last_month = strtotime("first day last month");
$last_three_month = strtotime("first day -3 month");

if($scheduled_job > $this_week) {
    echo 1;
}

if($scheduled_job < $this_week and $scheduled_job >= $last_week) {
    echo 2;
}

if(strtotime($date_job) > $this_month) {
    echo 3;
}

if($scheduled_job < $this_month and $scheduled_job >= $last_month) {
    echo 4;
}

if(strtotime($date_job) > $last_three_month) {
    echo 5;
} 

Nothing is being displayed. 什么都没有显示。 How do i solve? 我该如何解决?

I modified your code, if needed further modify your IF statements, but date creation works as expected, you get DateTime objects and you can do whatever you like from them: 我修改了您的代码,如果需要进一步修改IF语句,但是日期创建按预期工作,您将获得DateTime对象,并且可以从它们中进行任何操作:

$my_date = "29/02/2016";

//this week,last week, this month, last month and last 3 months
$scheduled_job =  DateTime::createFromFormat('d/m/Y', $my_date);

//test your date
//echo $scheduled_job->format('Y-m-d');

$this_week = new DateTime(date('Y-m-d',strtotime("first day this week")));
$last_week = new DateTime(date('Y-m-d',strtotime("last week monday")));
$this_month = new DateTime(date('Y-m-d',strtotime("first day this month")));
$last_month = new DateTime(date('Y-m-d',strtotime("first day last month")));
$last_three_month = new DateTime(date('Y-m-d',strtotime("first day -3 month")));


if($scheduled_job > $this_week) {
    echo 1;
}

if($scheduled_job < $this_week and $scheduled_job >= $last_week) {
    echo 2;
}

if($scheduled_job > $this_month) {
    echo 3;
}

if($scheduled_job < $this_month and $scheduled_job >= $last_month) {
    echo 4;
}

if($scheduled_job > $last_three_month) {
    echo 5;
}

$dateJob is never defined (third and fifth if statement). 从未定义$dateJob (if语句的第三和第五个)。

Maybe did you meant $scheduled_job ? 也许您是说$scheduled_job吗?

Moreover, try to format $my_date in a different manner because if you use / as separator, this means m/d/y 此外,请尝试以其他方式设置$my_date格式,因为如果使用/作为分隔符,则意味着m/d/y

$my_date = "29-02-2016";

Simply do str_replace of '/' slash: 只需对str_replace '/' str_replace'/'斜杠:

$my_date = str_replace('/', '.', '29/02/2016');

Because strtotime documentation says: 因为strtotime文档说:

Dates in the m/d/y or dmy formats are disambiguated by looking at the separator between the various components: if the separator is a slash (/), then the American m/d/y is assumed; 通过查看各个组成部分之间的分隔符,可以消除m / d / y或dmy格式的日期的歧义:如果分隔符为斜杠(/),则假定为美国m / d / y; whereas if the separator is a dash (-) or a dot (.), then the European dmy format is assumed. 相反,如果分隔符是破折号(-)或点(。),则采用欧洲dmy格式。

I pref using the DateTime class. 我喜欢使用DateTime类。

$date = new \DateTime();

$thisMonday = $date->modify('first day of this week'); // to get the current week's first date
$lastMonday = $date->modify('last monday'); // to get last monday
$firstDayThisMonth = $date->modify('first day of this month'); // to get first day of this month
$firstDayLastMonth = $date->modify('first day of this month'); // to get first day of last month
$firstDayThreeMonthAgo = new \DateTime($firstDayThisMonth->format('Y-m-d') . ' - 3 months'); // first day 3 months ago

$my_date = str_replace('/', '.', "29/02/2016");
$scheduled_job = new \DateTime($my_date);

// Now you can do the checks.

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM