我的弹出窗口没有显示（Javascript / PHP）。 怎么了？

Question

I have connected my popup with a dynamical database but it doesn't show up.

I have this Javascript with PHP code:

        <?php
        $r=mysql_query("select * FROM mynews where cmsid='359' and status='1' order by ordid");
        while ($m = mysql_fetch_array($r))
            {
        ?>
        $(document).ready(function() {
        $.fancybox(
        '<div style="width:800px">
        <h2 style="width:100%; text-align:center; margin-bottom:15px; color:#323742;"><?php echo $m["mytitle"]; ?></h2>
        <p><?php echo $m["mydescr"];?></p></div>',          {
                'autoDimensions'    : true,
                'transitionIn'      : 'none',
                'transitionOut'     : 'none'
                }


        <?php
        }
        ?> 

</script>

Answer 1

i think you missed closing brass

<script type="text/javascript">
  <?php
    $r=mysql_query("select * FROM mynews where cmsid='359' and status='1' order by ordid");
    while ($m = mysql_fetch_array($r))
        {
    ?>
    $(document).ready(function() {
    $.fancybox(
    '<div style="width:800px">
    <h2 style="width:100%; text-align:center; margin-bottom:15px; color:#323742;"><?php echo $m["mytitle"]; ?></h2>
    <p><?php echo $m["mydescr"];?></p></div>',          {
            'autoDimensions'    : true,
            'transitionIn'      : 'none',
            'transitionOut'     : 'none'
            });
       });
    <?php
    }
    ?> 
  </script>