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numpy从线性函数生成数据

[英]numpy generate data from linear function

Say I wanted to generate 100 or so data points from a linear function what's the best way to go about it? 假设我想从线性函数生成100个左右的数据点,那么最好的方法是什么?

An example linear function y = 0.4*x + 3 + delta 线性函数的示例y = 0.4*x + 3 + delta

where delta is a random value drawn from a uniform distribution between -10 and +10 其中delta是从-10和+10之间的均匀分布中抽取的随机值

I want delta to be generated for each data point to give some perturbation to the data. 我希望为每个数据点生成delta,以对数据进行一些扰动。

import numpy as np

d = np.random.uniform(-10, 10)

This seems to fit the bill for delta although I'm unsure exactly how to generate the rest incorporating this. 这似乎符合三角洲的法案,虽然我不确定如何产生其余的纳入这个。

I don't know how you wanted to generate x, but this will work: 我不知道你想如何生成x,但这会起作用:

In [7]: x = np.arange(100)

In [8]: delta = np.random.uniform(-10,10, size=(100,))

In [9]: y = .4 * x +3 + delta

在此输入图像描述

It all rather depends on what x values you want to evaluate your function. 这完全取决于您想要评估函数的x值。 Assuming you want to plot from -50 to 50 just use x = np.arange(-50,50) but then you need d = np.random.uniform(-10, 10, x.size) . 假设你想从-50到50绘制,只需使用x = np.arange(-50,50)但是你需要d = np.random.uniform(-10, 10, x.size)

Then just run your function: y = 0.4*x + 3 + delta . 然后运行你的函数: y = 0.4*x + 3 + delta

On the other hand if you want a linearly spaced x you can also use np.linspace or for logarithmicly spaced x : np.logspace . 另一方面,如果你想要一个线性间隔的x你也可以使用np.linspace或对数间隔xnp.logspace

In the end it could look like: 最后它看起来像:

x = np.linspace(0, 100, 1000) # 1000 values between 0 and 100
# x = np.arange(-50, 50) # -50, -49, ... 49, 50
delta = np.random.uniform(-10, 10, x.size)
y = 0.4*x + 3 + delta

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