MySQL SELECT WHERE多个值

Question

I have a table like this

Creating google charts, so i need couple of DB queries to create JSON. Everything is done but having hard time with DB query.

1. Solved this query.
2. Need to select all billable and all nonbillable hours, sum of them grouped by date. So to get for each day sum of billable and non-billable hours.

Currently i have single query,

$json = array();
$sql = "SELECT SUM(TIME_TO_SEC(`hours`)) as seconds,date FROM `am_am2_time_tracking` WHERE is_billable = 1 GROUP BY date";
$result = $conn->query($sql);
while($row = $result->fetch_assoc())
{   
    $bil_hours = floatval($row['seconds'] / 60 / 60);
    $json[] = array('date'=>$row['date'],'bill_hours'=>$bil_hours);
}
echo json_encode($json);

which gives me this json:

[{"date":"2016-02-03","bill_hours":12.5},{"date":"2016-02-04","bill_hours":6},{"date":"2016-02-12","bill_hours":3},{"date":"2016-02-13","bill_hours":4},{"date":"2016-02-18","bill_hours":1.25},{"date":"2016-02-19","bill_hours":1},{"date":"2016-02-26","bill_hours":1.75},{"date":"2016-02-27","bill_hours":0.5}]

But instead of creating new query, looking for better way to have both hours in single json.

Answer 1

您是否尝试进行以下查询

$sql = "SELECT SUM(TIME_TO_SEC(`hours`)) as seconds,date FROM `am_am2_time_tracking` GROUP BY date, is_billable";