如何在PHP中一次从两个不同的文件夹中取消链接两个图像

Question

I have this code which is supposed to delete two image files from two diffrent folders at the same time. The issue is, only one image is deleted. the other is not. I have tried different methods but still the same issue.

Below is my code.

<?php
$colname_albumedit = "-1";
if (isset($_GET['arf'])) {
    $colname_albumedit = $_GET['arf'];
}

$query_album = "SELECT * FROM galbum WHERE alID = '" . $colname_albumedit . "'";
$result_album = mysqli_query($connKcla, $query_album);
$row_album = mysqli_fetch_assoc($result_album);
$totalRows_album = mysqli_num_rows($result_album);

$query_album_images = "SELECT * FROM gimage WHERE alID = '" . $colname_albumedit . "'";
$result_album_images = mysqli_query($connKcla, $query_album_images);
$row_album_images = mysqli_fetch_assoc($result_album_images);
$totalRows_album_images = mysqli_num_rows($result_album_images);


if ((isset($_POST["form_del"])) && ($_POST["form_del"] == "adalbumdel")) {

    $target = "../gallery/albums/";
    $targett = "../gallery/images/";

    $imID = $_GET['arf'];
    $sql_query = "SELECT alImage FROM galbum WHERE alID = $imID";
    $photoresult = mysqli_query($connKcla, $sql_query);
    $row_album = mysqli_fetch_assoc($photoresult);

    if (($row_album['alImage']) != 0) {
        unlink($target . $row_album['alImage']);
    }

    $sql_queryy = "SELECT albumRef FROM gimage WHERE albumRef = $imID";
    $photoresultt = mysqli_query($connKcla, $sql_queryy);
    $row_album_images = mysqli_fetch_assoc($photoresultt);

    if (($row_album_images['albumRef']) != 0) {
        unlink($targett . $row_album_images['albumRef']);
    }

    $query_del = "DELETE FROM galbum WHERE alID = $colname_albumedit";
    $result_del = mysqli_query($connKcla, $query_del);

    $queryy_del = "DELETE FROM gimage WHERE alID = $colname_albumedit";
    $resultt_del = mysqli_query($connKcla, $queryy_del);

    if ($result_del && $resultt_del) {
        $updateGoTo = "confirm.php";
        if (isset($_SERVER['QUERY_STRING'])) {
            $updateGoTo .= (strpos($updateGoTo, '?')) ? "&" : "?";
            $updateGoTo .= $_SERVER['QUERY_STRING'];
        }
        header("Location: " . $updateGoTo);
    } else {
        header("Location: error.php");
    }
}    

The table gImage looks like this:

CREATE TABLE IF NOT EXISTS gimage ( 
    imID bigint(20) NOT NULL AUTO_INCREMENT, 
    imImage varchar(255) DEFAULT NULL, 
    albumRef bigint(20) DEFAULT NULL, 
    PRIMARY KEY (imID), KEY alID (albumRef) 
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=4 ;

Answer 1

Think, just replace this code

$sql_queryy = "SELECT albumRef FROM gimage WHERE albumRef = $imID";
$photoresultt = mysqli_query($connKcla, $sql_queryy);
$row_album_images = mysqli_fetch_assoc($photoresultt);

if (($row_album_images['albumRef']) != 0) {
    unlink($targett . $row_album_images['albumRef']);
}

with this code.

$sql_queryy = "SELECT imImage FROM gimage WHERE albumRef = $imID";
$photoresultt = mysqli_query($connKcla, $sql_queryy);
$row_album_images = mysqli_fetch_all($photoresultt);
foreach ($row_album_images as $row) {
    unlink($targett . $row[0]);
}

Recommendation

Rename your variable $imID cause it is in reality the albumId. As you can see in your code in the lines

$imID = $_GET['arf'];
$sql_query = "SELECT alImage FROM galbum WHERE alID = $imID";