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不用枚举就可以枚举枚举值

[英]Foreach enum values without casting

I have to cast enum but I want this to be as generic as possbile. 我必须强制枚举,但我希望它像possbile一样通用。 How can I replace the Cast<XX>() part with propertyType ? 我如何用propertyType替换Cast<XX>()部分?

foreach (var prop in MainType.GetProperties().Where(x => x.PropertyType.IsEnum))
{
     var x = new { name = prop.Name, values = new List<object>() };

     foreach (var v in Enum.GetValues(prop.PropertyType).Cast<XX>())
         x.values.Add(new { p = v.GetAttribute<DescriptionAttribute>().Description, 
                            c = v.GetAttribute<DefaultValueAttribute>().Value });

     o.Add(x);
}


    public static TAttribute GetAttribute<TAttribute>(this Enum value) where TAttribute : Attribute
    {
        var type = value.GetType();
        var name = Enum.GetName(type, value);
        return type.GetField(name)
            .GetCustomAttributes(false)
            .OfType<TAttribute>()
            .SingleOrDefault();
    }

public enum JobApplicationState : short
{
    [Description("Active")]
    [DefaultValue(typeof(string), "bg-primary text-highlight")]
    Active = 1,
    [Description("Passive")]
    [DefaultValue(typeof(string), "bg-grey text-highlight")]
    Passive = 2,
    [Description("Rejected")]
    [DefaultValue(typeof(string), "bg-danger text-highlight")]
    Rejected = 3,
    [Description("Accepted")]
    [DefaultValue(typeof(string), "bg-success text-highlight")]
    Accepted = 4
}

THIS WORKED! 这工作!

foreach (MemberInfo m in prop.PropertyType.GetFields())
{
    if (m.GetCustomAttributes(typeof(DescriptionAttribute), true).FirstOrDefault() != null && m.GetCustomAttributes(typeof(DefaultValueAttribute), true).FirstOrDefault() != null)
        {
             x.values.Add(
                 new
                 {
                     p = ((DescriptionAttribute)m.GetCustomAttributes(typeof(DescriptionAttribute), true).FirstOrDefault()).Description,
                     c = ((DefaultValueAttribute)m.GetCustomAttributes(typeof(DefaultValueAttribute), true).FirstOrDefault()).Value
        });
    } 
}

You should realize that an enum is nothing more than a named wrapper around an integral value. 您应该意识到,枚举只不过是围绕整数值的命名包装器。 I've described some details on how enums work here: Cast int to enum in C# . 我已经在这里描述了枚举的工作方式的一些细节: 在C#中将int转换为枚举

The question here is to get attributes values from an enum. 这里的问题是从枚举中获取属性值。 As you might imagine, this question is about getting attributes from the type , not about getting attributes from the value (there's no such thing). 您可能会想到,这个问题是关于从类型获取属性的,而不是关于从获取属性的(没有这样的事情)。 Still, if you call a method like void Foo<T>(T myEnum) , the type T will hold all the necessary info, even though 'in real life' the value of myEnum is passed around as an integral type. 尽管如此,如果您调用诸如void Foo<T>(T myEnum)之类的方法,则类型T将保存所有必要的信息,即使“在现实生活中” myEnum的值也作为整数类型传递。

From this you can also deduce that you're actually looking for the attributes of the MemberInfo 's of T , since you're looking for the members of the type (eg the enum). 由此,您还可以推断出您实际上是在寻找TMemberInfo的属性,因为您正在寻找该类型的成员(例如,枚举)。 Again, all the details are in my post on how enums work. 同样,所有细节都在我的文章中有关枚举的工作方式。 Hence the answer: 因此,答案是:

foreach (MemberInfo m in prop.PropertyType.GetFields())
{
    // use m.GetAttribute(...) 
}

Why don´t you simply cast to Enum : 您为什么不简单地投给Enum

foreach (var v in Enum.GetValues(prop.PropertyType).Cast<Enum>())

Now you can call your extension-method on every element within the returned list. 现在,您可以在返回列表中的每个元素上调用扩展方法。

v.GetAttribute<MyType>()

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