匹配以相同元音字母开头和结尾的单词

Question

I am trying to come up with a regex to match words starting and ending with same vowel. My question is, is this an elegant all-encompassing solution or am i missing something? So far this is what I have come up after a quick brainstroming. My preferred environment is javascript/python without special libraries etc. Thanks for helpful suggestions.

• soln. 1) re = /(^[aeiou])\\w+\\1/i;
• soln. 2) re = /(^[aeiou])[a-zA-Z]+\\1/i;
• console.log(re.test("abcda")); //true
• console.log(re.test("abcdo")); //false

Answer 1

Words can be matched using a word boundary \\b :

var re = /\b([aeiou])[a-z]+\1\b/i;

The regex demo

The regex matches:

• \\b - leading word boundary (because the pattern after it matches a word character)
• ([aeiou]) - Group 1 capturing a vowel from the specified range
• [az]+ - one or more letters (both upper- and lowercase since the /i modifier is used)
• \\1 - backreference to the vowel captured with the first group
• \\b - trailing word boundary