[英]'expected expression' error within if statement
I'm having to learn c++ on the fly with my data structure class. 我必须通过我的数据结构类即时学习c ++。 I only previously have experience with java which is why my error feels trivial but I am struggling to figure it out.
我以前只有Java的经验,这就是为什么我的错误让人觉得微不足道,但是我正在努力弄清楚。 I am getting an 'expected expression' error and am unsure what it is telling me.
我收到“期望的表达式”错误,不确定它告诉我什么。 I have tried swapping out my literal expressions out for ASCii code values and that sort of thing.
我已经尝试将我的文字表达式换成ASCii代码值之类的东西。 The error occurs on all of my if statements.
该错误发生在我所有的if语句上。 I do have all of my needed '#include' statements.
我确实有所有需要的“ #include”语句。 Thanks for any help.
谢谢你的帮助。
stack<double> doublestack;
char *input = new char[255]();
char *token = new char[255]();
cout << "Enter a valid postfix expression" << endl;
cin.getline(input, 255);
token = strtok(input, " ");
while (token != NULL) {
if (token* == '*')
{
double b = doublestack.top();
double a = doublestack.top();
doublestack.pop();
doublestack.pop();
doublestack.push(b * a);
}
else if (token* == '/')
{
double b = doublestack.top();
double a = doublestack.top();
doublestack.pop();
doublestack.pop();
doublestack.push(b / a);
}
else if (token* == '+')
{
double b = doublestack.top();
double a = doublestack.top();
doublestack.pop();
doublestack.pop();
doublestack.push(b + a);
}
else if (token* == '-')
{
double b = doublestack.top();
double a = doublestack.top();
doublestack.pop();
doublestack.pop();
doublestack.push(b - a);
}
else
{
doublestack.push(atof(token));
}
token = strtok(NULL, " ");
}
If it helps to know, I am getting a postfix expression and pushing the numbers into a stack. 如果有帮助,我将获得一个后缀表达式并将这些数字推入堆栈。 When I find an operational character, I will pop the top two numbers to perform the operation.
找到操作字符后,我将弹出前两个数字以执行操作。 Once the postfix is finished, I should be left with one number and that is the answer to the postfix expression.
后缀完成后,我应该留下一个数字,这就是后缀表达式的答案。
The error messages are as follows... 错误消息如下...
stack1.cpp:24:20: error: expected expression
if (token* == '*')
^
stack1.cpp:32:25: error: expected expression
else if (token* == '/')
^
stack1.cpp:40:25: error: expected expression
else if (token* == '+')
^
stack1.cpp:48:25: error: expected expression
else if (token* == '-')
In this case, a = b 在这种情况下,a = b
double b = doublestack.top();
double a = doublestack.top();
doublestack.pop();
doublestack.pop();
guess you u want get last value(top()), then remove it from stack(pop()), then get next last value and so on 猜猜你要获取最后一个值(top()),然后将其从堆栈中移除(pop()),然后获取下一个最后一个值,依此类推
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