Pymongo中是否有一个复杂的查询生成器？

Question

The structure of document is as follows:

{ "_id" : 1, "name" : "Demographics", "parent" : 0 }

I want do like as follow:

pyList=list(db.collection.find({"parent":0},{"_id":1}))
colList=list(db.collection.find({"parent":$in:[pyList]},{"name":1}))

As i have achieved my requirement but I am sure even that this is not optimized. Kindly direct me to any such framework of mongodb where I can write one query and my requirement will be achieved.

Please be gentle as I am newbie.

Answer 1

It depends on your definition of optimized. If you mean "number of lines of code" then you might want to check the possibilities offered by MongoDB's aggregation framework .

If you mean "memory and speed" optimization, I would not recommend using anything else but MongoDB's basic find command. The reason for this is that a well-indexed collection will always provide faster query results when compared with an aggregation command. From what I see in your code, the only change I would recommend is to make sure the "parent" key is also indexed.