[英]recording user voice android
I am trying to make an application which should first record the user's voice and then calculate different things (eg spectrum) from the recorded file. 我正在尝试制作一个应用程序,该应用程序应首先记录用户的语音,然后从记录的文件中计算出不同的内容(例如频谱)。 I can't play the recorded file (I can't find that file - does it even record?). 我无法播放录制的文件(我找不到该文件-甚至可以录制吗?)。 Here is my code: 这是我的代码:
package com.example.annik.puhesovellus;
import android.media.MediaPlayer;
import android.media.MediaRecorder;
import android.net.Uri;
import android.os.Bundle;
import android.os.Environment;
import android.support.design.widget.FloatingActionButton;
import android.support.design.widget.Snackbar;
import android.support.v7.app.AppCompatActivity;
import android.support.v7.widget.Toolbar;
import android.view.View;
import java.io.File;
import java.io.IOException;
public class DisplayAanitysIkkuna extends AppCompatActivity {
private String mFileName;
private MediaRecorder mRecorder;
private MediaPlayer mPlayer;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_display_aanitys_ikkuna);
Toolbar toolbar = (Toolbar) findViewById(R.id.toolbar);
setSupportActionBar(toolbar);
FloatingActionButton fab = (FloatingActionButton) findViewById(R.id.fab);
fab.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
Snackbar.make(view, "Replace with your own action", Snackbar.LENGTH_LONG)
.setAction("Action", null).show();
}
});
mFileName = Environment.getExternalStorageDirectory()+"/audiorecorder.3gpp";
}
public void ButtonTapped(View view) {
switch(view.getId()) {
case R.id.start:
try {
beginRecording();
}catch(Exception e){
e.printStackTrace();
}
break;
case R.id.stop:
try {
stopRecording();
}catch(Exception e) {
e.printStackTrace();
}
break;
case R.id.play:
try {
playRecording();
}catch(Exception e) {
e.printStackTrace();
}
break;
case R.id.stopPlaying:
try {
stopPlaying();
}catch(Exception e) {
e.printStackTrace();
}
break;
}
}
private void stopPlaying() {
mPlayer.release();
mPlayer = null;
}
private void playRecording() throws Exception{
ditchMediaPlayer();
MediaPlayer mPlayer = MediaPlayer.create(this, Uri.parse(mFileName));
mPlayer.start();
}
private void ditchMediaPlayer() {
if(mPlayer != null) {
try {
mPlayer.release();
}catch(Exception e) {
e.printStackTrace();
}
}
}
private void beginRecording() throws IOException {
ditchMediaRecorder();
File outFile = new File(mFileName);
if(outFile.exists()) {
outFile.delete();
}
mRecorder = new MediaRecorder();
mRecorder.setAudioSource(MediaRecorder.AudioSource.MIC);
mRecorder.setOutputFormat(MediaRecorder.OutputFormat.THREE_GPP);
mRecorder.setAudioEncoder(MediaRecorder.AudioEncoder.AMR_NB);
mRecorder.setOutputFile(mFileName);
mRecorder.prepare();
mRecorder.start();
}
private void ditchMediaRecorder() {
if(mRecorder != null) {
mRecorder.release();
}
}
private void stopRecording() {
if(mRecorder != null) {
mRecorder.stop();
}
}
}
And I know the indents are not correct because I pasted the code badly... Do you have any ideas why this code doesn't work? 而且我知道缩进是不正确的,因为我粘贴的代码很糟糕...您是否知道为什么此代码不起作用? It gives two errors: "Should have subtitle controller already set" but I read that I don't need to mind that and "QCMediaPlayer mediaplayer NOT present" and I read that this means that my platform doesn't support QCMediaPlayer..? 它给出了两个错误:“应该已经设置了字幕控制器”,但是我读到我不需要介意,并且“ QCMediaPlayer媒体播放器不存在”,并且我读到这意味着我的平台不支持QCMediaPlayer。 Does this code record a file and it just can't play it or does it fail to record a file? 该代码是否记录了文件并且无法播放,还是记录失败? How can I record user voice and process the saved file? 如何录制用户声音并处理保存的文件?
I believe that problem is in playRecording()
. 我相信问题在于playRecording()
。 When you type MediaPlayer mPlayer = ...
it creates a new variable with scope inside that method. 当您键入MediaPlayer mPlayer = ...
它将在该方法内部创建一个具有范围的新变量。 You are not using your class MediaPlayer
variable. 您没有使用MediaPlayer
类变量。 Try to change 尝试改变
MediaPlayer mPlayer = MediaPlayer.create(this, Uri.parse(mFileName));
to 至
mPlayer = MediaPlayer.create(this, Uri.parse(mFileName));
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