正则表达式匹配所有封闭''（2单引号）

Question

I am looking for a regex that will provide me with capture groups for each set of 2 single quotes ( '' ) within the single-quoted strings ( 'string' ) that are part of a comma-separated list. For instance the string 'tom''s' would have a single group between the m and the s . I've come close but keep getting tripped up by either erroneously matching up with the enclosing single quotes or with only capturing some of the 2 single quotes within a string.

Example Input

'11','22'',','''33','44''','''55''','6''''6'

Desired Groups (7, shown in parens)

 '11','22(''),','('')33','44('')','('')55('')','6('')('')6'

For context, what I'm ultimately attempting to do is replace these 2 single quotes within the comma-separated sequence of strings with another value in order to make subsequent parsing easier.

Note also that commas may be contained within the single quoted strings.

Answer 1

You cannot match the double single quotes like that with Python re module. You can just match the single-quoted entries and capture the inner part of each entry, and using a lambda, replace the '' inside with a mere .replace :

import re
p = re.compile(r"'([^']*(?:''[^']*)*)'")
test_str = "'11','22'',','''33','44''','''55''','6''''6'"
print(p.sub(lambda m: "'{}'".format(m.group(1).replace("''", "&")), test_str))

See IDEONE demo , output: '11','22&,','&33','44&','&55&','6&&6'

The regex is '([^']*(?:''[^']*)*)' :

• ' - opening '
• ( - Capture group #1 start
• [^']* - zero or more non- '
• (?:''[^']*)* - 0+ sequences of '' followed with 0+ non- '
• ) - Capture group #1 end
• ' - closing '