[英]PHP regex: find the first occurrence of a given pattern in a string
my string can be 我的绳子可以是
new-york-10036
or 要么
chicago-55036
the desired result is 理想的结果是
new-york
chicago
and i basically want to remove all the string that come after the first dash - followed by a number 我基本上想删除第一个破折号之后的所有字符串-后跟一个数字
seems easy but i don't know how 似乎很简单,但我不知道如何
You can use Negative Lookahead, like so: 您可以使用负前瞻,如下所示:
(.+)(?=\-\d)
The regex reads: "get me everything that is not followed by exactly one dash and exactly one number after that". 正则表达式显示为:“让我得到的所有不带一个破折号和一个跟在其后的数字”。
Given the input new-york-10036
the regex is going to capture only new-york
. 给定输入
new-york-10036
,正则表达式将仅捕获new-york
。 In PHP you can get the matched string with: 在PHP中,您可以通过以下方式获取匹配的字符串:
$string = 'new-york-10036';
$regex = '/(.+)(?=\-\d)/';
preg_match($regex, $string, $return);
echo $return[0] . "\n";
It outputs new-york
. 它输出
new-york
。
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