Ajax调用PHP函数

Question

I want to call a php file from js. I do not have experience with ajax so i don't really know how to use it properly. I use this function :

function start(cod){
    var result =0;
    $.ajax({
        type: "POST",
        url: "CheckDetails.php",
        datatype: "html",
        async: false,
        data: {cod: cod},
        success: function(data) {
            result = data;
        }
    });
    return result;
}

And the PHP file :

<?php

check($_POST['cod']);

function check($cod)
{
    mysqli_report(MYSQLI_REPORT_STRICT);
    $dbhandle = 0;
    try {
        $username = 'root';
        $password = '';
        $hostname = 'localhost';
        $dbhandle = new mysqli($hostname, $username, $password, 'db') ;
    } catch (Exception $e ) {
        echo "Service unavailable";
        exit;
    }
    $name = '';
    $date = '';
    $hour = '';

    $result = 0;
    $codeResult = mysqli_query($dbhandle, "SELECT name, date, hour FROM records WHERE cod = '$cod'");
    if (!$codeResult) {
        echo('Database error: ' . mysqli_error($dbhandle));
    } else
        if ($row = mysqli_fetch_assoc($codeResult)) {
            $name = $row{"name"};
            $date = $row{"date"};
            $hour = $row{"hour"};
            $result = 1;
        }
    echo $result;
}

?>

But it seems it doesnt work. I dont really know where is the problem.

Answer 1

it seems in your DB-query you only read the first result set from your table, and you don't return the results. If I get your intentions right you would have in your last 'else' clause something like:

 ...
 else {
   while($row = mysqli_fetch_array($codeResult)) {
      $data[] = array("name" => $row["name"], "date" => $row["date"], "hour" => $row["hour"]);
      }
   }
 ...

with having $data declared as array earlier in the code. This way you would have your query results stored in a $data array which you could return as it is or as a json_encoded object.