[英]Choose multiple class name and get childnode inside that class with PHP DOMXpath
<div id="conti">
<div class="no_matter"></div>
<div class="row-0">
<b></b>
<span>
<i>"child node that i want to get"</i>
</span>
</div>
<div class="row-1">
<b></b>
<span>
<i>"child node that i want to get"</i>
</span>
</div>
<div class="row-0">
<b></b>
<span>
<i>"child node that i want to get"</i>
</span>
</div>
<div class="row-1">
<b></b>
<span>
<i>"child node that i want to get"</i>
</span>
</div>
...
...
class row-0 and row-1 repeats itself
...
...
</div>
This is the HTML that i want to parse and get contents. 这是我要解析和获取内容的HTML。 I want
text node inside <i> tag
. 我希望
text node inside <i> tag
。 I am using DOMDocument
and DOMXpath
我正在使用
DOMDocument
和DOMXpath
$dom = new DOMDocument();
$dom->loadHTMLFile('http://www.meal.org/anter.php');
$dom->preserveWhiteSpace = true;
$xpath = new DOMXPath($dom);
$row = $xpath->query('//*[@class="row-0" ]'); //my problem begins there. I want both 'row-0' and 'row-1'. How i am gonna choose multiple class?
//and than how i am gonna get `<i>` tag inside every `row-0` and `row-1` class and get the text node?
You can do all that with the following XPath query: 您可以使用以下XPath查询执行所有操作:
//*[starts-with(@class,"row-")]/span/i/text()
MDN on starts-with : MDN on starts-with :
The
starts-with
checks whether the first string starts with the second string and returns true or false.starts-with
检查第一个字符串是否以第二个字符串开头并返回true或false。
If you are interested in all text nodes in these rows, so also the ones in the b
tags, and any other tags that might be in those rows, then use the double slash: 如果您对这些行中的所有文本节点感兴趣,那么
b
标记中的文本节点以及可能在这些行中的任何其他标记也会感兴趣,然后使用双斜杠:
//*[starts-with(@class,"row-")]//text()
$iTags = $xpath->query('//div[@class="row-0" or @class="row-1"]/span/i');
foreach ($iTags as $iTag) {
var_dump(trim($iTag->nodeValue));
}
I'm not fammiliar with XPath, so I'm looping trough each <div>
element using DOMDocument()
. 我不熟悉XPath,所以我使用
DOMDocument()
循环遍历每个<div>
元素。 Check wheter it has a attribute class with value row-0 or row-1. 检查它是否具有值为row-0或row-1的属性类。 If so then get each element
<i>
and dump the nodeValue. 如果是,则获取每个元素
<i>
并转储nodeValue。
foreach($dom->getElementsByTagName('div') as $div){
if($div->getAttribute('class') == 'row-0' OR $div->getAttribute('class') == 'row-1'){
foreach($div->getElementsByTagName('i') as $i){
var_dump($i->nodeValue);
}
}
}
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