PHP查询以数组格式返回数据库

Question

Let's say I query my database and I get the following result

+---+---+-------+
| N | M | score |
+---+---+-------+
| 0 | 2 |    14 |
| 1 | 0 |    22 |
+---+---+-------+

After doing $res = $db->query($query); Is there anyway to store this information in an array. For example, I've tried doing this

      $array = array();    
      while ($row = mysql_fetch_array($res, MYSQL_NUM)) {
            array_push($array, array($row[0], $row[1], $row[2]));
      }

Because I have this idea that everytime it fetches a row into a numeric array,

$row[0] = 0 , $row[1] = 2, $row[2] = 14 for the first row and

$row[0] = 1, $row[1] = 0, $row[2] = 22 for the second row

Please do correct me if I'm wrong because I'm pretty sure I'm wrong :O

EDIT: Reason why I'm asking what $row contains is because I would like to store each row into an array to form a multi dimensional array. For example, {"E":[[0,1,86],[1,0,96]]} after json_encode . So in order to do that, I need to push each row as an array into another array ie push the first row as array [0,1,86] into $array followed by pushing the second row as array [1,0,96] . I doubt I can achieve this by doing an associative array. once again correct me if I'm wrong.

Answer 1

Your code is substantially fine ( mysql_fetch_array is a typo, I think).

The only note: You have to init $array before while loop, otherwise your array_push will fail.

So, your code is working, but solution provided in comment is better, because is shorter and more efficient: with mysql_fetch_array you already obtain your desired array, so you have simply to add it to your array, without specifying each key. Also, as per php docs , the $array[] = syntax is more efficient that array_push() if adding only one element to array.

$array = array();
while( $row = mysqli_fetch_array( $res, MYSQL_NUM ) )
{
    $array[] = $row;
}

If you prefer, you can obtain same result using mysqli_fetch_all() :

$array = mysqli_fetch_all( $res, MYSQLI_NUM );

[Edit:] Obviously, the last two solutions will work only if you want retrieve all fields returned by the query.

[Edit 2:] To obtain JSON in your desired format, simply add this line at the end of your code:

$json = json_encode( array( 'E' => $array ) );