用正则表达式替换最小/最大十进制长度

Question

I've found on this forum the following regex to replace any number into the smallest possible decimal length:

number.toFixed(maxDecimal).replace(/\\.?0+$/, '');

It works really well, except for one case: when number is equal to 49.9999999, it returns 5 instead of 50 when I put maxDecimal to 0. I'm a little bit lost with regex and would appreciate if you come up with a suggestion.

Answer 1

Just remove the question mark ? since that makes 50 reduce to 5 because the regex says 0 or 1 occurrence of decimal point followed by 1 or more 0 's. You don't want that because 0 in 50 would match that 0+ part because decimal point is optional. Use this regex this to make sure you replace only decimal part aptly.

>47.79955965.toFixed(5).replace(/(\.0+){0,1}$/, '');
"47.79956"
>number=49.9999999
49.9999999
> number.toFixed(5).replace(/(\.0+){0,1}$/, '');
"50"
> number.toFixed(0).replace(/(\.0+)?$/, '');
"50"