[英]Ajax Not Working With C# Controller Action With 2D Array Parameter
My Ajax is not hitting my controller action. 我的Ajax没有达到我的控制器动作。 What could be the reason?
可能是什么原因?
My Controller Action 我的控制器动作
public ActionResult Save_Data(string [][] rosterArray, int Pricelist_Id, int Group_Id)
My Ajax 我的阿贾克斯
$.ajax({
url: '@Url.Action("Save_Data", "PriceListMaster")',
type: 'Post',
async: false,
contentType: 'application/json',
dataType: "json",
data: { "rosterArray": rosterArray, "Pricelist_Id": "2", "Group_Id": $("#Group_Id").val() },
//data: JSON.stringify({ "Item_Code": Item_Code, "IPD_Price": IPD_Price, "OPD_Price": OPD_Price, "EMS_Price": EMS_Price }),
success: function (data) {
debugger
if (data.success)
{
alert('Data Saved Successfully.');
location.reload();
} else {
alert(data.error_msg);
}
}
}
If you are using type: 'Post'
in AJAX, that means you need to add a Request type in Controller. 如果您使用
type: 'Post'
是AJAX中的type: 'Post'
,则意味着您需要在Controller中添加请求类型。
Try using this in controller, 尝试在控制器中使用它,
[HttpPost]
public ActionResult Save_Data(string [][] rosterArray, int Pricelist_Id, int Group_Id)
Use httpPost
in the Method for define type of response. 在方法中使用
httpPost
定义响应类型。
at client side 在客户端
$.ajax({
url: '@Url.Action("Save_Data", "PriceListMaster")',
type: 'Post',
async: false,
contentType: 'application/json',
dataType: "json",
data: { "rosterArray": JSON.stringify(rosterArray), "Pricelist_Id": "2", "Group_Id": $("#Group_Id").val() },
//data: JSON.stringify({ "Item_Code": Item_Code, "IPD_Price": IPD_Price, "OPD_Price": OPD_Price, "EMS_Price": EMS_Price }),
success: function (data) {
debugger
if (data.success)
{
alert('Data Saved Successfully.');
location.reload();
} else {
alert(data.error_msg);
}
}
}
and your controller code can be like this: 您的控制器代码可以像这样:
[HttpPost]
public ActionResult Save_Data(string rosterArray, int Pricelist_Id, int Group_Id)
{
string [][] convertedArray = JsonConvert.DeserializeObject<string [][]>(rosterArray);
}
Hope this works Note: But you need to incude using Newtonsoft.Json;
希望这行得通注意:但是您需要
using Newtonsoft.Json;
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