删除IP地址的最后一个八位位组

Question

This is my code:

ip = ("192.143.234.543/23 
       192.143.234.5/23 
       192.143.234.23/23")

separateOct = (".")
ipNo4Oct = line.split(separateOct, 1) [0] 
print (ipNo4Oct)

The IPs come from a text file and I have done my for loops right.

The result I get is:

192
192
192

But I want this result:

192.143.234
192.143.234
192.143.234

How do I get the result I want?

Answer 1

You can use almost the same code, with some slicing and join :

>>> ipNo4Oct = ip.split(separateOct) [0:3]
>>> '.'.join(ipNo4Oct)
'192.143.234'

Or for the entire string (considering it can be splitted to lines as your code suggests):

>>> for line in ip:
        ipNo4Oct = line.split(separateOct) [0:3]
        '.'.join(ipNo4Oct)

'192.143.234'
'192.143.234'
'192.143.234'

Answer 2

With

ip = ("192.143.234.543/23",
       "192.143.234.5/23",
       "192.143.234.23/23")

for line in ip:
    separator = "."
    ipNo4Oct = separator.join(line.split(separator, 3)[:-1])
    print (ipNo4Oct)

you re-join your 3 parts using the separator.