php更新查询不会更新数据库
[英]php Update query won't update database
问题描述
I am working on a project and right now I am making a system where I edit posts with ckeditor. 
我正在做一个项目，现在正在制作一个系统，在其中可以使用ckeditor编辑帖子。 If I edit text with ckeditor it doesn't update and I don't see any errors telling me what is wrong. 如果我使用ckeditor编辑文本，它不会更新，并且看不到任何错误告诉我什么地方不对。 Help me if you can. 如果可以的话，请帮助我。
<html>
<head>
<link href='https://fonts.googleapis.com/css?family=Titillium+Web:400,300,200' rel='stylesheet' type='text/css'>
<meta charset="utf-8">
<script src="//cdn.ckeditor.com/4.5.7/standard/ckeditor.js"></script>
<link rel="stylesheet" type="text/css" href="cke.css">
<title>Nieuws</title>
</head>
<?php
include 'db.php';
include 'repeatForm.php';
if (isset($_POST['id'])) {
if (is_numeric($_POST['id'])) {
$id = $_GET['id'];
$title = $_POST['cTitle'];
$content = $_POST['ed1'];
if ($title == '' || $content == '') {
$error = 'Fout: vul alle velden in';
//laat form zien
repeatForm($id,$title,$content,$error);
} else {
$stmt = $dbcon->prepare("UPDATE content SET contentTitle = :title, contentText = :text WHERE contentId = :nummer");
$stmt->bindParam(':title', $title, PDO::PARAM_STR);
$stmt->bindParam(':content', $content, PDO::PARAM_STR);
$stmt->bindParam(':nummer', $id, PDO::PARAM_STR);
$stmt->execute($title,$content,$id);
header("Location: index.php");
}
} else {
echo "Fout";
header("Location: index.php");
}
}
else {
if (isset($_GET['id']) && is_numeric($_GET['id']) && $_GET['id'] > 0) {
$id = $_GET['id'];
$query = $dbcon->query("SELECT * FROM content WHERE contentId='$id'");
$r = $query->fetch();
if ($r['contentId'] == $id) {
$title = $r['contentTitle'];
$content = $r['contentText'];
}
//laat form zien met variabelen
repeatForm($id,$title,$content);
} else {
echo "No results";
header("refresh:1.5;url='index.php';");
}
}
?>
2 个解决方案
解决方案1
1 已采纳 2016-03-07 15:10:20
Stay consistent when you name your variables, database fields, and input names. 在命名变量，数据库字段和输入名称时保持一致。 You'll end up making a lot less mistakes. 您最终将犯下的错误更少了。 For example, instead of using $content , use $text . 例如，使用$text代替使用$content 。 In your SQL, use :text and :id instead. 在您的SQL中，改用:text和:id 。
$stmt = $dbcon->prepare("UPDATE content SET contentTitle = :title, contentText = :text WHERE contentId = :id");
$stmt->bindParam(':title', $title, PDO::PARAM_STR);
$stmt->bindParam(':text', $text, PDO::PARAM_STR);
$stmt->bindParam(':id', $id, PDO::PARAM_INT); // expecting an integer, not string
$stmt->execute(); // no need to pass parameters again
Personally, I don't like to use bindParam as it seems unnecessary. 就个人而言，我不喜欢使用bindParam因为这似乎是不必要的。 Another way is to do: 另一种方法是：
$stmt = $dbcon->prepare("UPDATE content SET contentTitle = :title, contentText = :text WHERE contentId = :id");
$stmt->execute(array(':title' => $title, ':text' => $text, ':id' => $id));
Or better if the SQL is relatively short: 如果SQL相对较短，则更好：
$stmt = $dbcon->prepare("UPDATE content SET contentTitle = ?, contentText = ? WHERE contentId = ?");
$stmt->execute(array($title, $text, $id)); // the order matters
解决方案2
0 2016-03-07 14:56:43
在此行中用text替换content ：
$stmt->bindParam(':text', $content, PDO::PARAM_STR);
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