正则表达式提取字符串

Question

I have the following expression:

MN=Abc123,MN=sssa,MN=abc adsa 1,MN=&3ams d'amé,MN=dat,CB=ds,CB=ds

How can I extract one by one the expressions following MN= ? eg: firstly I want to extract Abc123 , secondly I wnat sssa and so on ...

Appreciate your answer!

Answer 1

Use a capture group:

"[A-Z]{2}=([^,]+)"

Then get the first group form your matched object.

Or if the language you are dealing for supports the look-around you can use a positive look-behind in order to directly match the expected parts:

"(?<=[A-Z]{2}=)[^,]+"

Answer 2

If your regex environment supports lookbehind, you can extract desired information with this regex:

Environment supporting Lookbehind

(?<=MN=)(.*?)(?=,) 

Environment not supporting Lookbehind

(?:MN=)(.*?)(?=,)

Your desired result will be stored in Group 1, aka $1

Based on your input string, here is result

Abc123
sssa
abc adsa 1
&3ams d'amé
dat

See live demo here