SQL通过包含字符串排序

Question

I am trying to sort by whether '/us/' is in a url. I currently have:

SELECT is_live, store_url from my_table where item_id = 1306085 
ORDER BY (CASE WHEN store_url LIKE '%/us%' THEN 1 ELSE 0 END) DESC

Is there a cleaner way to do this, or is the above the only way? Conceptually, I'm looking for something a bit more readable, such as:

ORDER BY store_url.contains('/us/') DESC

Answer 1

you may try this:

SELECT is_live, store_url from my_table where item_id = 1306085 
ORDER BY instr(store_url, '/us/');

or:

SELECT is_live, store_url from my_table where item_id = 1306085 
ORDER BY instr(store_url, '/us/') > 0 ;

SQLFiddle

Answer 2

You could create a function :

CREATE FUNCTION mycontains (s text, matchText VARCHAR(255))
RETURNS INT DETERMINISTIC
RETURN (CASE WHEN s LIKE CONCAT("%", matchText, "%") THEN 1 ELSE 0 END);

and use it like

SELECT is_live, store_url from my_table where item_id = 1306085 
ORDER BY mycontains(store_ul, "/us/") DESC

Note: There is already a contains function, I think it works with geometric objects, that is why I named this mycontains.