[英]MySQL returns only the first character of the fields, but works fine on local
I don't know what is going on exactly, but all only the first character is returned for all my columns when I uploaded my website. 我不知道究竟发生了什么,但是当我上传我的网站时,我的所有列都只返回了第一个字符。 It works perfectly fine on a local machine.
它在本地机器上运行得非常好。
I found a similar question here, but I didn't manage to find the answer: 我在这里找到了类似的问题,但我找不到答案:
https://stackoverflow.com/questions/10507848/mysql-query-returns-only-the-first-letter-of-strings-only-when-page-is-viewed-on https://stackoverflow.com/questions/10507848/mysql-query-returns-only-the-first-letter-of-strings-only-when-page-is-viewed-on
// Log Table Query
unset($stmt);
$stmt = $db->stmt_init();
$stmt = $db->prepare( "SELECT * FROM logs ORDER BY `id` DESC" );
$stmt->store_result();
$stmt->bind_result($r_id, $r_time, $r_logger, $r_message, $r_category);
$stmt->execute();
while( $stmt->fetch() )
{
var_dump($r_message);
var_dump($r_category);
}
$stmt->close();
This outputs on localhost for example: 这在localhost上输出,例如:
string(5) "Hello"String(3) "Cow"
string(5)“Hello”String(3)“Cow”
But on the live server: 但在实时服务器上:
string(1) "H"String(1) "C"
string(1)“H”String(1)“C”
Any ideas? 有任何想法吗?
Edit 编辑
I think that this applies only to string types. 我认为这仅适用于字符串类型。 The integer types return for example:
整数类型返回例如:
int(2893)
INT(2893)
I'm assuming that your database or table config is similar to your localhost (better to double check your table). 我假设您的数据库或表配置与您的localhost类似(最好仔细检查您的表)。 I noticed one mistake:
我注意到一个错误:
1. You called store_result()
before calling execute()
. 1.在调用
execute()
之前调用了store_result()
execute()
。 As per http://php.net/manual/en/mysqli-stmt.store-result.php execute()
should be called first. 根据http://php.net/manual/en/mysqli-stmt.store-result.php,应首先调用
execute()
。
See my code this might solve your problem: 看到我的代码,这可能会解决您的问题:
/* unsetting doesn't matter you're
going to overwrite it anyway */
unset($stmt);
/* you dont need to initialize $stmt with $db->stmt_init(),
$db->prepare() method will create it for you */
$stmt = $db->stmt_init();
$stmt = $db->prepare("SELECT * FROM logs ORDER BY `id` DESC");
/* execute the query first before storing
the result and binding it your variables */
if (!$stmt->execute()) {
echo "query execution error";
exit();
}
/* store the result */
$stmt->store_result();
/* then bind your variables */
$stmt->bind_result($r_id, $r_time, $r_logger, $r_message, $r_category);
/* fetch data and display */
while($stmt->fetch()) {
var_dump($r_message);
var_dump($r_category);
}
$stmt->close();
Let me know if this solved your problem. 如果这解决了您的问题,请告诉我。
Alternatively, you can use the straight forward way since you're not giving any input parameter like WHERE first_name LIKE <input here>
to your query: 或者,您可以直接使用,因为您没有向查询提供任何输入参数,例如
WHERE first_name LIKE <input here>
:
$result = $db->query("SELECT * FROM logs ORDER BY `id` DESC");
if ($result === false) {
echo "query execution error";
exit();
}
/* You can use either MYSQLI_NUM or MYSQLI_ASSOC os MYSQLI_BOTH
see php.net for more info */
echo "<pre>";
while($line = $result->fetch_array(MYSQLI_NUM)) {
print_r($line);
echo "\n";
}
echo "</pre>";
As suggested in the question you linked, try the code without unset($stmt)
and $stmt = db->stmt_init()
Instead, you might use free_result()
正如您链接的问题所示,请尝试不使用
unset($stmt)
和$stmt = db->stmt_init()
而是使用free_result()
// Log Table Query
$stmt->free_result(); //Free old results first
$stmt = $db->prepare( "SELECT * FROM logs ORDER BY `id` DESC" );
$stmt->store_result();
$stmt->bind_result($r_id, $r_time, $r_logger, $r_message, $r_category);
$stmt->execute();
while( $stmt->fetch() )
{
var_dump($r_message);
var_dump($r_category);
}
$stmt->close();
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.