在LINQ中连接父和子集合以获得单个合并输出

Question

I have a collection of items which each contain a secondary collection. I need to generate a list of new items based off the total set of secondary items. Eg if you have a list of dogs and each dog has a list of friends, I need a total list of all dog friends for all dogs.

Normally I would do this with SelectMany but the difficulty here is my secondary objects do not contain a reference back to the parent object, and the new list needs to contain fields from both secondary and parent objects. ie as below

var dogs = List<Dog>
var newList = dogs.SelectMany(i => i.DogFriends).Select(dogFriend => new NewObject
            {
                fieldOne = dog.propertyOne,
                fieldTwo = dog.propertyTwo
                fieldThree = dogFriend.propertyOne
            });

In the above, I have no reference to dog however, so I cannot select those.

What I'm looking for is a way to do a join on the two tables as in SQL, so you can select values from both objects. But I want the total values to match the total number of child objects. Ie if you have 3 dogs with 3 friends each, the final list will have 9 objects.

How can I achieve this with LINQ?

Answer 1

Indeed .SelectMany(...) is the answer. Another usage is:

var data = dogs
    .SelectMany(d => d.DogFriends.Select(df => new { d, df })
    .Select(x =>
        // Now you can use both d and df
        new NewObject {
            fieldOne = x.d.propertyOne,
            fieldTwo = x.d.propertyTwo
            fieldThree = x.df.propertyOne
        }
    )
    .ToArray();

Even simpler is to use the query LINQ notation. This basically translates to the above at compile time.

var data = from d in dogs
           from df in d.DogFriends
           select new NewObject {
               fieldOne = d.propertyOne,
               fieldTwo = d.propertyTwo
               fieldThree = df.propertyOne
           }

Answer 2

使用.SelectMany重载https://msdn.microsoft.com/en-us/library/bb534631%28v=vs.110%29.aspx

var query = petOwners .SelectMany( petOwner => petOwner.Pets, (petOwner, petName) => new { petOwner, petName } )