[英]Go fmt float64 issue
I've come across a bit of a gotcha in my noob understanding of go fmt package 我对go fmt包的理解中遇到了一些问题
It relates to the following code: 它涉及以下代码:
import "fmt" 导入“fmt”
func main() {
var smallFloat float64 = 0.123456789
var bigFloat float64 = 123456789000
fmt.Println(fmt.Sprintf("%f", smallFloat))
fmt.Println(fmt.Sprintf("%f", bigFloat))
}
The output is: 输出是:
0.123457
123456789000.000000
I don't want to use scientific notation so thought %f would suit my needs.I can see from the formatting page ( https://golang.org/pkg/fmt/ ) it says: 我不想使用科学记数法,所以认为%f符合我的需要。我可以从格式化页面( https://golang.org/pkg/fmt/ )看到它说:
The default precision for %e and %f is 6; for %g it is the smallest number of digits necessary to identify the value uniquely.
Is there a way I can use the fmt package that would allow me represent the full decimal value of smallFloat while at the same time not appending 6 zeros to the end of bigFloat? 有没有办法可以使用fmt包,它允许我代表smallFloat的完整十进制值,同时不会在bigFloat的末尾附加6个零?
You can use strconv.FormatFloat
with prec set to -1: 您可以使用
strconv.FormatFloat
并将prec设置为-1:
fmt.Println(strconv.FormatFloat(big, 'f', -1, 64))
fmt.Println(strconv.FormatFloat(small, 'f', -1, 64))
prints 版画
123456789000
0.123456789
Playground: http://play.golang.org/p/7p8xnQ_BzE . 游乐场: http : //play.golang.org/p/7p8xnQ_BzE 。
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