[英]How can I set a variable to a text input and then make it appear on screen
I am making a text based game for school and I am stuck with trying to set a variable as an text input. 我正在为学校制作一款基于文本的游戏,但我坚持尝试将变量设置为文本输入。 What I would like to happen is the player type start into the input and it do what is inside of the if statement. 我想发生的是播放器类型从输入开始,并且执行if语句中的内容。 However from there I would like the player to enter a username and then it set the variable of "name" to what they input but with out it saving the name as "start". 但是从那里我希望播放器输入一个用户名,然后将“ name”变量设置为他们输入的内容,但没有将其保存为“ start”。
//js
var name = "";
var beginBeenTo = false;
if (beginBeenTo == false) {
if (input == "START") {
beginBeenTo = true;
page = page + 1;
healthPoints = 25;
soundEveningBreeze.play();
$("#welcome_message").show().insertBefore("#placeholder").delay(3000).fadeOut(3000);
$("<br><p class='text'>You there, what is your name?</p>").hide().insertBefore("#placeholder").delay(7000).fadeIn(3000);
if (input != "" || namingBeenTo == false) {
name = input;
}
}
}
document.getElementById("print_name").innerHTML = name;
Quite simply, watch for some event ( keyup
in my case), check if the input value is START
, if so ask for a username. 很简单,注意一些事件(在我的情况下为keyup
),检查输入值是否为START
,如果是这样则要求输入用户名。
var started = false; var username = ''; $('input').on('keyup', function(){ var tmpValue = $(this).val(); if(started){ username = tmpValue } if(tmpValue === 'START') { started = true; $(this).val('') $(this).attr('placeholder','Username') } $('#username').text(username) })
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script> <span id="username"></span> <br> <input type="text" placeholder="Type START to play">
it could be done with use of function like this : 可以通过使用如下函数来完成:
var name = "";
$("form").submit(function() {
var input = $("#command_input").val().toUpperCase();
if (input == "START") {
name = $("#input_form").val();
}
}
document.getElementById("print_name").innerHTML = name;
you were missing one of #(hashtag) 您缺少#(#标签)中的一个
And this code would work 而且这段代码可以工作
Thanks & Cheers 谢谢与欢呼
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