[英]Symfony2/Twig - how to set template file contents as variable?
In Symfony 2.8 I've got SharedBundle
, where I keep views and other things I share between other bundles, including the whole layout that should be extended by other bundles' views. 在Symfony 2.8中,我有了
SharedBundle
,在那里我保存了其他bundle之间共享的视图和其他内容,包括应该由其他bundle视图扩展的整个布局。
That shared layout has some typical blocks, from which sidebar
block should be different for different bundles. 该共享布局具有一些典型的块,对于不同的束,
sidebar
块应该是不同的。
Currently I did an ugly workaround: 目前我做了一个丑陋的解决方法:
In SharedBundle
sidebar container: 在
SharedBundle
侧边栏容器中:
{% if sidebarcontent is defined %}
{{ sidebarcontent|raw }}
{% else %}
SIDEBAR NOT FOUND
{% endif %}
And in other bundles (here: BundleA
) in every view that extends the shared main view: 在扩展共享主视图的每个视图中的其他bundle(此处为:
BundleA
)中:
{% extends 'SharedBundle:layout.html.twig' %}
{% block sidebar %}
{% include 'BundleA:_partials:sidebar.html.twig' %}
{% endblock %}
{% set sidebarcontent = block('sidebar') %}
But that doesn't look good, I think. 但我觉得这看起来不太好看。 Is there a better way?
有没有更好的办法?
I think this is a valid approach. 我认为这是一种有效的方法。 The only simplification I can think of is not using the variable
sidebarcontent
. 我能想到的唯一简化就是不使用变量
sidebarcontent
。
You can use block('sidebar')
inside the if
statement: 你可以在
if
语句中使用block('sidebar')
:
{% if block('sidebar')|length > 0 %}
{{ sidebarcontent|raw }}
{% else %}
SIDEBAR NOT FOUND
{% endif %}
Make sure the block exists before checking it's content, so initialise it with an empty string: 在检查内容之前确保该块存在,因此使用空字符串初始化它:
{% block sidebar %}{% endblock %}
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