[英]How can I query this sort of relationship in Eloquent?
The schemas go as following: 模式如下:
Likes
id (pk)
UserID
FreestyleID
Freestyle:
id (pk)
BeatId
Beat:
id (pk)
trackId
Track:
id (pk)
GenreId
Genre:
id (pk)
Title
Really I would like to get a collection of Freestyles by their genre ID where they have likes. 真的,我想通过他们喜欢的流派ID来获得Freestyle的集合。 I have tried quite a few things including relationships such as:
我已经尝试了很多事情,包括诸如以下的关系:
Genre model:
public function beat()
{
return $this->hasManyThrough('App\Beat', 'App\Track', 'GenreId', 'TrackId');
}
However, the above will return results like the following because each track can have up to three beats.: 但是,以上内容将返回如下结果,因为每个曲目最多可以包含三个节拍:
Let me know if you need to see anything more. 让我知道您是否还需要查看其他内容。
you are on the correct way, but you will need a bit more of code. 您使用的是正确的方法,但是您将需要更多的代码。 First of all, you can change your Genre's function name to beats() - just for convention, because it will return multiple registers :P.
首先,您可以将流派的函数名称更改为beats()-仅出于约定,因为它将返回多个寄存器:P。 Second, with hasManyThrough you will get all Beats related (through Track) with Genre.
其次,通过hasManyThrough,您将获得与流派相关的所有Beats(通过Track)。 Then, you can access to the Freestyles related with that Beat:
然后,您可以访问与该Beat相关的自由式:
Beat: 击败:
public function freestyles()
{
return $this->hasMany('App\Freestyle');
}
FreeStyle: 自由式:
public function beat()
{
return $this->belongsTo('App\Beat');
}
public function likes()
{
return $this->hasMany('App\Like');
}
has('freestyles.likes')
has('freestyles.likes')
So, you can do a function like this (Genre Model): 因此,您可以执行以下功能(流派模型):
public function beatsWithLikes()
{
return $this->beats()->has('freestyles.likes');
}
I hope It helps you. 希望对您有帮助。
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