[英]How to create an AttributeSyntax with a parameter
I'm trying to use Roslyn to create a parameter that looks something like this: 我正在尝试使用Roslyn创建一个看起来像这样的参数:
[MyAttribute("some_param")]
Now I can easily create the AttributeSyntax
but can't figure out how to add an argument to the ArgumentList
porperty using the .AddArguments(ExpressionSyntax)
method. 现在我可以轻松创建
AttributeSyntax
但无法弄清楚如何使用.AddArguments(ExpressionSyntax)
方法向ArgumentList
AttributeSyntax
添加参数。 I'm just not sure what I need to do to create the appropriate expression. 我只是不确定我需要做什么才能创建合适的表达式。
I'm a fan of the SyntaxFactory.Parse*
methods. 我是
SyntaxFactory.Parse*
方法的粉丝。 (They're usually easier to understand) (他们通常更容易理解)
You could use the following to generate the attribute you're looking for: 您可以使用以下命令生成您正在寻找的属性:
var name = SyntaxFactory.ParseName("MyAttribute");
var arguments = SyntaxFactory.ParseAttributeArgumentList("(\"some_param\")");
var attribute = SyntaxFactory.Attribute(name, arguments); //MyAttribute("some_param")
var attributeList = new SeparatedSyntaxList<AttributeSyntax>();
attributeList = attributeList.Add(attribute);
var list = SyntaxFactory.AttributeList(attributeList); //[MyAttribute("some_param")]
Alternatively you could use hand-crafted approach from Kirill's RoslynQuoter tool. 或者,您可以使用Kirill的RoslynQuoter工具手工制作的方法。 But I think the fact that no one wants to write that code without his tool is telling... ;)
但我认为没有人想要在没有他的工具的情况下编写代码的事实就是在说; ...)
The manual approach looks like: 手动方法如下:
var attributeArgument = SyntaxFactory.AttributeArgument(
SyntaxFactory.LiteralExpression(SyntaxKind.StringLiteralExpression, SyntaxFactory.Token(default(SyntaxTriviaList), SyntaxKind.StringLiteralToken, "some_param", "some_param", default(SyntaxTriviaList))));
var otherList = new SeparatedSyntaxList<AttributeArgumentSyntax>();
otherList = otherList.Add(attributeArgument);
var argumentList = SyntaxFactory.AttributeArgumentList(otherList);
var attribute2 = SyntaxFactory.Attribute(name, argumentList);
In your example you want to add a StringLiteralExpression
as your argument. 在您的示例中,您希望添加
StringLiteralExpression
作为参数。
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