Strct标准：仅变量应通过引用传递

Question

I have this code

$maxSize="44400000";
$allowedExts = array("jpg","jpeg","docx","png","JPG");
$extension = end(explode(".", $_FILES["file"]["name"])); 

and giving me error shown below.

The Main problem is with the above line.

Strict standards: Only variables should be passed by reference

Answer 1

You have to create one more variable:

$maxSize="44400000";
$allowedExts = array("jpg","jpeg","docx","png","JPG");
$extension = explode(".", $_FILES["file"]["name"]);
$final_ext = end($extension);

But it's better to use pathinfo to do this.

$path = $_FILES['file']['name'];
$ext = pathinfo($path, PATHINFO_EXTENSION);

Answer 2

As end function only accepts argument that must be passed by reference you should do this :

$maxSize="44400000";
$allowedExts = array("jpg","jpeg","docx","png","JPG");
$explode = explode(".", $_FILES["file"]["name"]);
$extension = end($explode);

read more http://php.net/manual/en/function.end.php