将pandas df写入Excel，并将其保存到副本中

Question

I have a pandas dataframe and I want to open an existing excel workbook containing formulas, copying the dataframe in a specific set of columns (lets say from column A to column H) and save it as a new file with a different name.

The idea is to update an existing template, populate it with the dataframe in a specified set of column and then save a copy of the Excel file with a different name.

Any idea?

What I have is:

  import pandas
  from openpyxl import load_workbook

 book = load_workbook('Template.xlsx')
 writer = pandas.ExcelWriter('Template.xlsx', engine='openpyxl') 
 writer.book = book
 writer.sheets = dict((ws.title, ws) for ws in book.worksheets)

 df.to_excel(writer)

 writer.save()

Answer 1

The below should work, assuming that you are happy to copy into column A. I don't see a way to write into the sheet starting in a different column (without overwriting anything).

The below incorporates @MaxU's suggestion of copying the template sheet before writing to it (having just lost a few hours' work on my own template workbook to pd.to_excel)

import pandas as pd
from openpyxl.utils.dataframe import dataframe_to_rows
from shutil import copyfile

template_file = 'Template.xlsx' # Has a header in row 1 already
output_file = 'Result.xlsx' # What we are saving the template as

# Copy Template.xlsx as Result.xlsx
copyfile(template_file, output_file)

# Read in the data to be pasted into the termplate
df = pd.read_csv('my_data.csv') 

# Load the workbook and access the sheet we'll paste into
wb = load_workbook(output_file)
ws = wb.get_sheet_by_name('Existing Result Sheet') 

# Selecting a cell in the header row before writing makes append()
#  start writing to the following line i.e. row 2
ws['A1']
# Write each row of the DataFrame
# In this case, I don't want to write the index (useless) or the header (already in the template)
for r in dataframe_to_rows(df, index=False, header=False):
    ws.append(r)

wb.save(output_file)

Answer 2

try this:

df.to_excel(writer, startrow=10, startcol=1, index=False, engine='openpyxl')

Pay attention at startrow and startcol parameters