在 sql 查询中使用 Like 时不返回任何结果

Question

I am having syntax issue with MySQL with PHP.

My code:

$q['item_desc LIKE \'%?%\'"'] = array($criteria);

but it gets translated to SQL Query:

SELECT `Item`.`id`, `Item`.`item_desc`, `Item`.`row_num`, `Item`.`shelf_num`, `Item`.`shelf_loc`, `Item`.`datetime` FROM `inventory`.`items` AS `Item` WHERE `item_desc` LIKE '%'10'%'"

I believe I need to get rid of the single quotes inside the % . How do I do this?

Answer 1

There is an un needed double quote in there.

Try

$q['item_desc LIKE \'%?%\'']

or

$q["item_desc LIKE '%?%'"]