[英]matching the pattern to a regular expression in java
i am trying to match following pattern 我正在尝试匹配以下模式
(any word string)/(any word string)Model(any word string)/(any word string)
example to match 匹配的例子
abc/pqrModellmn/xyz
kfkf/flfk/jgf/lflflflMModelkfkfkf/kfkfk
etc. I tried something like 等等,我尝试过类似
Pattern p = Pattern.compile("\D*\\\D*Model\D*\\");
Matcher m = p.matcher(fileEntry.getAbsolutePath());
System.out.println("The match is:" + m.find());
\\
is used as escape sequence for Java string literal, so escape it. \\
用作Java字符串文字的转义序列,因此请对其进行转义。 /
, not \\
, to match /
. /
而不是\\
来匹配/
。 Try this: 尝试这个:
import java.util.regex.*;
class Test {
static class Hoge {
public String getAbsolutePath() {
return "abc/pqrModellmn/xyz";
//return "kfkf/flfk/jgf/lflflflMModelkfkfkf/kfkfk";
}
}
public static void main(String[] args) throws Exception {
Hoge fileEntry = new Hoge();
Pattern p = Pattern.compile("\\D*/\\D*Model\\D*/\\D*");
Matcher m = p.matcher(fileEntry.getAbsolutePath());
System.out.println("The match is:" + m.find());
}
}
In regex word is captured by \\w
, so I have slightly different regex 在正则表达式中,单词被
\\w
捕获,所以我的正则表达式略有不同
\w+/\w+Model\w+/\w+
Your final code will look like 您的最终代码如下所示
public static void main(String[] args) {
String rx = "\\w+/\\w+Model\\w+/\\w+";
Pattern p = Pattern.compile(rx);
Matcher m = p.matcher(fileEntry.getAbsolutePath());
System.out.println("The match is:" + m.find());
}
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.