[英]Accepting Input from Command Line in C
How do I use scanf()
IN C to accept multiple inputs from the command line? 如何使用scanf()
IN C从命令行接受多个输入? I'm trying to get a name, followed by an arbitrary number of values from a user, on the same line. 我试图在同一行上获取一个名称,然后从用户那里获取任意数量的值。 I know the scanf()
function is space/new line delimited. 我知道scanf()
函数是用空格/换行符分隔的。
For example the user enters: dog 2 5 1 例如,用户输入:dog 2 5 1
I know scanf()
will read the "dog", but how do I get it to read the following values. 我知道scanf()
会读取“ dog”,但是如何获取它来读取以下值。 I can't use scanf("%s, %d, %d, %d", a, b, c, d)
because there could be more than, or less than 3 values entered. 我不能使用scanf("%s, %d, %d, %d", a, b, c, d)
因为可能输入的值大于或小于3。
You could pass arguments to the main function itself. 您可以将参数传递给main函数本身。 The prototype for main is 主要的原型是
int main(int argc, char* argv[]);
You could use this to read the command line arguments. 您可以使用它来读取命令行参数。 argc gives the total number of arguments (separated by a space), and argv is a vector that holds it. argc给出参数的总数(以空格分隔),而argv是保存它的向量。
For example user will enter: ./yourExecutable dog 2 5 1
In this case the number of arguments would be 5 (including the name of your executable) and argv[0]
would be your executable, argv[1] would be your "dog"
and so on. 例如,用户将输入: ./yourExecutable dog 2 5 1
在这种情况下,参数数量将为5(包括可执行文件的名称),而argv[0]
将成为您的可执行文件,argv [1]将成为您的"dog"
等等。
You can read the whole line to a string buffer using fgets()
. 您可以使用fgets()
将整行读取到字符串缓冲区。
Then split by spaces using strtok()
. 然后使用strtok()
按空格分隔。
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