如何在jQuery中使用文档准备功能重定向

Question

I want to redirect after call the DOM. This is my script.

    <script>
    $(document).ready(function(){
        $.get("<?php echo $url; ?>", function(data, status){
            alert(data);
        });
    });
    </script>

But I want to do like this.It's not working can anyone help me. Iupdated my coding.If i use window.location.href='trip_details.php' and alert box its not working.

    $username="cde-stng";
    $password="12345666";
    $msg="Welcome To Safetrip Nigeria";

    $url="http://121.241.242.114:8080/bulksms/bulksms?username=".$username."&password=".$password."&type=0&dlr=1&destination=".$mobile."&source=".$mobile."&message=".$msg;



    <script>
    $(document).ready(function(){
        $.get("<?php echo $url; ?>", function(data, status){
            //alert(data);
            window.alert('Trip Closed');
            window.location.href='trip_details.php';
        });
    });
    </script>

Answer 1

You are adding alert() between the function.

Remove this line window.alert('Trip Closed') window.location.href='trip_details.php';

and then add this

window.location.href='trip_details.php';

Answer 2

What's the use of this $url and $.get here? Please let me know what exactly you're trying to achieve here.

From what I understand, when you load the DOM, you want to show the alert message "Trip Closed", and then redirect to the trip_details.php. If so, there's no need ot this $.get.

You could try this:

$(document).ready(function(){
  alert("Trip Closed");
  window.location.href='trip_details.php';
});

Hope this helps.

Peace! xD

Answer 3

I don't see any problem with your code. You should look into the AJAX request. You can try PostMan to perform a GET request and check what gets returned.

If there is error related to Access Control you can use dataType: 'jsonp' to your request. This solved my problem when I was working on Google API.

Try this to log the data returned from the server in console:

$.ajax({
  method: "GET",
  url: "<?php echo $url; ?>",
  dataType: 'jsonp'
}).done(function(data){
  console.log(data);
});

If there are no errors, you can try this:

$.ajax({
  method: "GET",
  url: "<?php echo $url; ?>",
  dataType: 'jsonp'
}).done(function(data){
  alert( "Trip Closed" );
  window.location.href='trip_details.php';
});