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使用Armadillo库访问矩阵列而不创建数据副本

[英]Access column of matrix without creating copy of data, using Armadillo library

I have a (data/storage) class with a member arma::mat (a matrix), and I want to access just one column of this matrix ( arma::colvec ), but I don't want to create a copy of the data in the column. 我有一个(数据/存储)类与成员arma::mat (一个矩阵),我想只访问这个矩阵的一列( arma::colvec ),但我不想创建一个副本列中的数据。 Is there any way of achieving this? 有没有办法实现这个目标?

My first try was using .col(i) , but this returns a temporary, so taking a reference doesn't work. 我的第一次尝试是使用.col(i) ,但这会返回一个临时的,所以引用它不起作用。

Using .colptr(i) doesn't create a copy, but it also returns a double* instead of a vec , so it makes my life a bit hard. 使用.colptr(i)不会创建副本,但它也返回一个double*而不是vec ,所以它让我的生活变得有点困难。

struct Data
{
    mat A;

    /* constructors etc. */

    // reference to temporary (this is bad)
    const vec& getColumn(const uint i) { return A.col(i); }

    // doesn't create a copy, but doesn't return a vec either
    const double* getColumn2(const uint i) const { return A.colptr(i); }
}

The reason for wanting this is that the class has both vectors and matrices, and I want to make uniform getter and setter methods that access either one of the vectors, or a column in a matrix, depending on an index (for iteration purposes). 想要这个的原因是类有向量和矩阵,我想制作统一的getter和setter方法,它们可以访问其中一个向量,也可以访问矩阵中的一列,具体取决于索引(用于迭代目的)。

An example: 一个例子:

struct Data
{
    mat A;
    vec b;

    // getter
    const vec& operator()(const uint i) const
    {
        if (i == 0)
        {
            return b;
        }
        else if (i == 1)
        {
            // return first column of A
        }
        // etc.
    }

    // setter
    vec& operator()(const uint i)
    {
        // similar to above
    }
}

Solution

Based on the answer by zauguin I found the following way to achieve the wanted functionality: 根据zauguin回答,我找到了以下方法来实现所需的功能:

struct Data
{
    mat A;
    vec b;

    // getter
    subview_col<mat::elem_type> operator()(const uint i)
    {
        if (i == 0)
        {
            return b.col(0);
        }
        else if (i > 0 && i < (1 + A.n_cols()))
        {
            return A.col(i - 1);
        }
        else
        {
            // should probably do some error checking here
        }
    }

    // setter
    vec& operator()(const uint i)
    {
        // same as the above, but without consts in declaration
    }
}

This returns subview_col<mat::elem_type> instead of vec , but the functionality is similar/identical for my purposes. 这会返回subview_col<mat::elem_type>而不是vec ,但功能与我的目的相似/相同。 I am not sure of the performance impact of using .col(0) on a vec , but I'm not that worried. 我不确定使用.col(0)vec的性能影响,但我并不担心。

In arma, A.col(i) doesn't return a reference, but a temporary. 在arma中,A.col(i)不返回引用,而是临时引用。 You can return this temporary to get reference semantics. 您可以返回此临时值以获取引用语义。 With C++14, just write 使用C ++ 14,只需编写

    auto getColumn(const uint i) { return A.col(i); }

Otherwise, you have to return the proxy type, it is 否则,您必须返回代理类型,它是

    subview_col<mat::elem_type> getColumn(const uint i) { return A.col(i); }

If you have to return a vec instead of a subview_col<...> , you can use A.unsafe_col(i) , but you have to be sure, that you don't try to use it, after the lifetime of A ended. 如果你必须返回vec而不是subview_col<...> ,你可以使用A.unsafe_col(i) ,但你必须确保,在A的生命周期结束后你不会尝试使用它。 。 see here 看这里

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