[英]How to load an xml file into a SQL Server table
I searched in the internet and there is not good example for converting xml file into SQL Server table. 我在互联网上搜索,没有很好的示例将xml文件转换为SQL Server表。
I have this file: 我有这个文件:
<http://www.ims.gov.il/ims/PublicXML/isr_cities.xml>
This is a weather file for 15 cities (for the next 4 days). 这是15个城市(未来4天)的天气文件。
How can I load it to a flat table in SQL Server? 如何将其加载到SQL Server的平面表中?
I try and it just give me null's :-( 我尝试,它只是给我null :-(
I put out some value's that made problems but still I can't convert it to a big flat table. 我提出了一些会带来问题的价值,但仍然无法将其转换为大型平板。
How can I put out all the nodes inside the xml file? 如何放置xml文件中的所有节点?
Thanks! 谢谢!
You can try something like this (assuming you have your XML in a SQL Server variable called @input XML
): 您可以尝试执行以下操作(假设您将XML放在名为@input XML
的SQL Server变量中):
SELECT
LocationId = XC2.value('(LocationId)[1]', 'int'),
LocNameEng = XC2.value('(LocationNameEng)[1]', 'varchar(100)'),
TheDate = XCE.value('(../Date)[1]', 'DATE'),
ElementName = XCE.value('(ElementName)[1]', 'varchar(50)'),
ElementValue = XCE.value('(ElementValue)[1]', 'varchar(50)')
FROM
@input.nodes('/IsraelCitiesWeatherForecastEvening/Location') AS XT(XC)
CROSS APPLY
XC.nodes('LocationMetaData') AS XT2(XC2)
CROSS APPLY
XC.nodes('LocationData/TimeUnitData/Element') AS XTE(XCE)
That should give you at least some output and can server as a starting point for more exploration! 那应该至少给您一些输出,并且可以作为服务器进行更多探索的起点!
I think this might be what you want. 我想这可能就是您想要的。 After the call you can do with the XML what ever you want... 通话之后,您可以随心所欲地使用XML。
--you need to allow this:
sp_configure 'show advanced options', 1;
GO
RECONFIGURE;
GO
sp_configure 'Ole Automation Procedures', 1;
GO
RECONFIGURE;
GO
DECLARE @URL VARCHAR(MAX) = 'http://www.ims.gov.il/ims/PublicXML/isr_cities.xml';
DECLARE @xmlT TABLE (yourXML XML);
DECLARE @Response NVARCHAR(MAX);
DECLARE @XML XML;
DECLARE @Obj INT;
DECLARE @Result INT;
DECLARE @HTTPStatus INT;
DECLARE @ErrorMsg NVARCHAR(MAX);
EXEC @Result = sp_OACreate 'MSXML2.XMLHttp', @Obj OUT ;
EXEC @Result = sp_OAMethod @Obj, 'open', NULL, 'GET', @URL, false;
EXEC @Result = sp_OAMethod @Obj, 'setRequestHeader', NULL, 'Content-Type', 'application/x-www-form-urlencoded';
EXEC @Result = sp_OAMethod @Obj, SEND, NULL, '';
EXEC @Result = sp_OAGetProperty @Obj, 'status', @HTTPStatus OUT ;
INSERT @xmlT ( yourXML )
EXEC @Result = sp_OAGetProperty @Obj, 'responseXML.xml';
SELECT * FROM @xmlT;
the problem was in my local setting... 问题出在我的本地环境中...
here anyway my code after improving. 无论如何,在这里我的代码经过改进。 I still working on it... thank's to all of you! 我还在努力中...谢谢大家!
DECLARE @WeatherXML xml
SET @WeatherXML = ( SELECT * FROM
OPENROWSET (BULK 'C:\Stam\isr_cities.xml', SINGLE_BLOB) AS FileImport (XMLDATA))
SELECT
wXML.query('../../../LocationMetaData/LocationId').value('.','NVARCHAR(30)'),
wXML.query('../../../LocationMetaData/LocationNameEng').value('.','NVARCHAR(30)'),
wXML.query('../../../LocationMetaData/LocationNameHeb').value('.','NVARCHAR(30)'),
wXML.query('../../../LocationMetaData/DisplayLat').value('.','NVARCHAR(30)'),
wXML.query('../../../LocationMetaData/DisplayLon').value('.','NVARCHAR(30)'),
wXML.query('../Date').value('.','NVARCHAR(30)'),
wXML.query('ElementName').value('.','NVARCHAR(30)'),
wXML.query('ElementValue').value('.','NVARCHAR(30)')
FROM @WeatherXML.nodes('/IsraelCitiesWeatherForecastMorning/Location/LocationData/TimeUnitData/Element') AS XmlData(wXML)
I must need the element node, but for begining I did something like this: 我必须需要element节点,但首先我要做的是这样的:
DECLARE @WeatherXML xml
SET @WeatherXML = ( SELECT * FROM
OPENROWSET (BULK 'C:\Stam\isr_citiesNEW.xml', SINGLE_BLOB) AS FileImport (XMLDATA))
-- insert xml to [MOT_Temp_WeatherXML] table
INSERT INTO [dbo].[MOT_Temp_WeatherXML]
([LocationId]
,[LocationNameEng]
,[LocationNameHeb]
,[DisplayLat]
,[DisplayLon]
)SELECT
wXML.query('LocationId').value('.','NVARCHAR(30)'),
wXML.query('LocationNameEng').value('.','NVARCHAR(30)'),
wXML.query('LocationNameHeb').value('.','NVARCHAR(30)'),
wXML.query('DisplayLat').value('.','NVARCHAR(30)'),
wXML.query('DisplayLon').value('.','NVARCHAR(30)')
FROM @WeatherXML.nodes('/IsraelCitiesWeatherForecastMorning/Location/LocationMetaData') AS XmlData(wXML)
SELECT * FROM [MOT_Temp_WeatherXML]
after that i get in the results: 之后,我得到结果:
<LocationId>520</LocationId>
and so on... instead of just 520... 等等...而不是520 ...
but again, if i get the element node i will be happy... 但是再次,如果我得到了元素节点,我会很高兴...
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