[英]Update one value at multiple ID's in database table
$upload_files=implode(' ',$_GET['upload_files']);
$upload_user=",".$_GET['upload_user'];
echo $upload_files;
$sql = "UPDATE {$db_pr}files SET userID = CONCAT(userID,'".$upload_user."') WHERE id IN ('".$upload_files."')";
IN takes a comma-delimited string I believe. 我相信,IN采用逗号分隔的字符串。
try: 尝试:
$upload_files=implode("','",$_GET['upload_files']);
Well, I got the solution. I used for loop to achieve the result.
$upload_files=$_GET['upload_files'];
$upload_user=",".$_GET['upload_user'];
for ($i = 0, $count = count($upload_files); $i <= $count; $i++) {
$sql = "UPDATE {$db_pr}files SET userID = CONCAT(userID,'".$upload_user."') WHERE id = '".$upload_files[$i]."'";
$result = mysqli_query($mysqli,$sql) or die("Error occurred - tried to update file.");
}
echo "<div class='loginMessage loginSuccess'>Assigned Successfully!!!</div>";
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